1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ValentinkaMS [17]
3 years ago
13

A 10 kg rock that has been dropped from a 60 meter high cliff experiences an average force of air resistance of 30 N. Calculate

the KE at the bottom of the fall.
Physics
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

4086 J

Explanation:

The potential energy is transformed to kinetic energy less the frictional energy. Potential energy= mgh where m represent mass, g is acceleration due to gravity and h is the height of cliff

Since we have force of air resistance, work done due to air resistance will be product of force and distance

mgh-Fh= 0.5mv^{2}= KE

Substituting 10 Kg for m, 9.81 for g and 60 m for F then the kinetic energy at the bottom will be

KE= 10*9.81*60- (30*60)=4086 J

You might be interested in
Isabela is an astronomer studying stars A and B. Star A is farther away from Isabela and yet when Isabela observes the stars, th
kakasveta [241]

Answer: star A is more luminous

Explanation:

7 0
3 years ago
Two protons are released from rest when they are 0.750 {\rm nm} apart.
Alex787 [66]

Explanation:

Given:

m = 1.673 × 10^-27 kg

Q = q = 1.602 × 10^-19 C

r = 0.75 nm

= 0.75 × 10^-9 m

A.

Energy, U = (kQq)/r

Ut = 1/2 mv^2 + 1/2 mv^2

1.673 × 10^-27 × v^2 = (8.99 × 10^9 × (1.602 × 10^-19)^2)/0.75 × 10^-9

v = 1.356 × 10^4 m/s

B.

F = (kQq)/r^2

F = m × a

1.673 × 10^-27 × a = ((8.99 × 10^9 × (1.602 × 10-19)^2)/(0.075 × 10^-9)^2

a = 2.45 × 10^17 m/s^2.

4 0
3 years ago
In order to slide a heavy desk across the floor at constant speed in a straight line, you have to exert a horizontal force of 40
san4es73 [151]

Answer:

F = f from Newton’s first law.

Explanation:

since the desk is moved in a straight line at a constant speed, newton first law tell us that the two forces must be equal.

Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. since the table has been set in motion by the 400 N force, it will remain in motion unless it is been acted upon by an external force, and this means that the 400 N must be equal to the frictional force for it to have been in motion in the first instance.

3 0
3 years ago
Which officeholders are elected by the electoral college
NikAS [45]

Answer:Electoral Vote

Explanation:i did it before

4 0
2 years ago
PLEASE HELP ASAP!!!! A huge thanks to anyone who can help me with 14 problems. I'll do anything to return the favor. All true an
snow_lady [41]
Hello, I see you are in a jam. Lemme help.

1.) True
2.) True
3.) True
4.) True
5.) True

LOL these are all true ;)
4 0
3 years ago
Other questions:
  • Part a consider another special case in which the inclined plane is vertical (θ=π/2). in this case, for what value of m1 would t
    7·1 answer
  • The desert and tundra are alike because they both have
    15·2 answers
  • A block slides with no friction and hits a spring with spring constant k=2000 N/m. The block compresses the spring in a straight
    8·1 answer
  • What can you calculate using the equation P equals W/t​
    10·1 answer
  • Woman has a near point of 75.0 cm. What focal length, f, is necessary for the corrective lens so that he can hold his physics bo
    8·1 answer
  • (b) Figure 4 shows a car travelling on a motorway.
    9·1 answer
  • Two blocks, one of mass 5 kg and the other of mass 2 kg, are attached to opposite ends of a light string and hung vertically fro
    6·1 answer
  • What type of objects exert gravitational pull? (5 points) Only living objects Only space objects All objects having mass All sub
    7·1 answer
  • 5<br> b. What is the molecular shape of the molecule? (3 points)
    7·2 answers
  • During sublimation the particles in a solid?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!