A 10 kg rock that has been dropped from a 60 meter high cliff experiences an average force of air resistance of 30 N. Calculate
1 answer:
Answer:
4086 J
Explanation:
The potential energy is transformed to kinetic energy less the frictional energy. Potential energy= mgh where m represent mass, g is acceleration due to gravity and h is the height of cliff
Since we have force of air resistance, work done due to air resistance will be product of force and distance
Substituting 10 Kg for m, 9.81 for g and 60 m for F then the kinetic energy at the bottom will be
KE= 10*9.81*60- (30*60)=4086 J
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Answer:
Explanation:
<u>Given:</u>
- Current through the wire, passing through the origin,
- Current through the wire, passing through the y axis,
,
According to Ampere's circuital law, the line integral of magnetic field over a closed loop, called Amperian loop, is equal to times the net current threading the loop.
In case of a circular loop, the directions of magnetic field and the line element , both are along the tangent of the loop at that point, therefore,
.
is the circumference of the Amperian loop =
Therefore,
It is the magnetic field due to a current carrying wire at a distance r from it.
For the first wire, passing through the origin:
Consider an Amperian loop of radius 3.510 m, concentric with the axis of the wire, such that it passes through the point where magnetic field is to be found, therefore,
The magnetic field at the given point due to this wire is given by:
For the first wire, passing through the y-axis:
Consider an Amperian loop of radius (3.510+1.8) m = 5.310 m, concentric with the axis of the wire, such that it passes through the point where magnetic field is to be found, therefore,
The magnetic field at the given point due to this wire is given by:
The directions of current in both the wires are opposite therefore, the directions of the magnetic field due to both the wires are also opposite to that of each other.
Thus, the net magnetic field at is given by