X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
The number would stay the same because, for example, 6 - 0 can't be 0 so it would be 6.
Answer:
Step-by-step explanation:
Discussion
You haven't given us any choices. Always do that it you have them. Look for the graph that looks like the one below. It has the following characteristics
- It opens upward
- It lowest point is -1,1
- y never equals zero
- The y intercept is 0,4
Let x= cucumber plants
5x= tomato plants
6x+7= pepper plants
peppers = 19
therefore
6x+7=19
subtract 7 from both sides
6x= 12
divide both sides by 6
x=2
replace the x with 2
2= cucumber plants
10= tomato plants
hope this helps