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PolarNik [594]
3 years ago
15

There are two numbers that

Mathematics
2 answers:
maw [93]3 years ago
7 0

Answer:

Larger number is 20

Step-by-step explanation:

20 * -4 = -80

20 + (-4) = 16

Mumz [18]3 years ago
5 0

Answer

20

Step-by-step explanation:

-4*20=-80

-4+20=16

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Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.
igor_vitrenko [27]

Answer:

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7

So, the solution of the equation is

y = Ae^{m_{1} t} + Be^{m_{2} t}

where m₁ = 3 and m₂ = -7.

So,

y = Ae^{3t} + Be^{-7t}

Also,

y' = 3Ae^{3t} - 7e^{-7t}

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1      (1)

y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}

Substituting A into (1) above, we have

\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1      \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}

Substituting B into A, we have

A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}

Substituting A and B into y, we have

y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

So the solution to the differential equation is

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

6 0
4 years ago
What is the value of 12 (8 + 9)?<br> 105<br> 204<br> 357<br> 864
USPshnik [31]

Answer:

204

Step-by-step explanation:

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3 0
3 years ago
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A national survey by Gallup interviewed a random sample of 1014 adults and found that they had consumed on average 4.2 alcoholic
Rom4ik [11]

Answer:

Approximately normal

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

As the sample size is above 30, even though the underlying distribution is right-skewed, the shape of the sampling distribution of the sample means will be approximately normal.

5 0
3 years ago
A collection of stamps consists of 22¢ stamps and 40¢ stamps. The number of 22¢ stamps is three more than four times the number
Artemon [7]

Answer:

27

Step-by-step explanation:

Let :

Number of 40¢ = x

Number of 22¢ = 4x + 3

Total stamp value = $8.34 = (8.34 * 100) = 834¢

40¢x + 22¢(4x + 3) = 834¢

40x + 88x + 66 = 834

128x = 834 - 66

128x = 768

x = 768 / 128

x = 6

Number of 22¢ stamp:

4(6) + 3 = 24 + 3 = 27

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3 years ago
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Eduardwww [97]

Answer:

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Step-by-step explanation:

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3 years ago
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