Answer:
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The perimeter of a triangle is the sum of the length of their three sides
so
where
a,b,c are the length sides of the triangle
In this problem we have
substitute and solve for the missing length
B or 12 would be the correct choice!
Hope this helps and mark as brainliest please!
Answer:
36
Step-by-step explanation:
3 * 12 = 36
if there are 12 girls and 3 times more wore dress then 3 times 12 is 36.
Answer:
21. ΔUYZ <u>Obtuse</u>
22. ΔBCD <u>Right or Rectangle</u>
23. ΔADB <u>Acute</u>
24. ΔUXZ <u>Acute</u>
25. ΔUWZ <u>Right or Rectangle</u>
26. ΔUXY <u>Equiangular and acute</u>
Step-by-step explanation:
We need to classify each triangle by its angles.
Acute: They have 3 acute angles (less than 90 degrees).
Rectangle: The inner angle A is straight (90 degrees) and the other 2 angles are sharp. The sides that form the right angle are called legs (c and b), the other side hypotenuse.
Obtuse: The inner angle A is obtuse (more than 90 degrees). The other 2 angles are acute.
ΔUYZ Obtuse The inner angle Y is obtuse (more than 90°).
ΔBCD Right or Rectangle The inner angle C is straight (90°).
ΔADB Acute It has 3 acute angles (less than 90°).
ΔUXZ Acute It has 3 acute angles (less than 90°).
ΔUWZ Right or Rectangle The inner angle W is straight (90°).
ΔUXY Equiangular and acute Which means all the inner angles are equal (60°).
Answer:
Step-by-step explanation:
1) Eliminate parentheses:
0.1x +18.8 = -4 +2x
22.8 = 1.9x . . . . . . . . . add 4 - 0.1x
12 = x . . . . . . . . . . . . . divide by 1.9
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2) Eliminate parentheses:
-16 +4x = 0.8x +12.8
3.2x = 28.8 . . . . . . . . add 16 - 0.8x
x = 9 . . . . . . . . . . . . . .divide by 3.2
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<em>Comments on the solutions</em>
The expression we add in each case eliminates the constant on one side of the equation and the variable term on the other side. That leaves an equation of the form ...
variable term = constant
We choose to eliminate the smaller variable term (the one with the coefficient farthest to the left on the number line). Then the constant we eliminate is the on on the other side of the equation. This choice ensures that the remaining variable term has a positive coefficient, tending to reduce errors.
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You can work these problems by methods that eliminate fractions. Here, the fractions are decimal values, so are not that difficult to deal with. In any event, it is good to be able to work with numbers in any form: fractions, decimals, integers. It can save some steps.
