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Margarita [4]
2 years ago
14

Solve for x -

id="TexFormula1" title="\bold{x {}^{2} + 5x + 6 = 0}\\\\" alt="\bold{x {}^{2} + 5x + 6 = 0}\\\\" align="absmiddle" class="latex-formula">
ty! ~
​
Mathematics
1 answer:
Fed [463]2 years ago
3 0

The solution of the given quadratic equation is x=-2 or x=-3.

The given quadratic equation is x²+5x+6=0.

<h3>What are different methods to solve a quadratic equation?</h3>

The different methods of solving quadratic equations are factoring, completing the square or using the quadratic formula.

By using the splitting middle term method we can solve x²+5x+6=0.

That is, x²+2x+3x+6=0

⇒x(x+2)+3(x+2)=0

⇒(x+2)(x+3)=0

⇒(x+2)=0, (x+3)=0

⇒x=-2 or x=-3.

Therefore, the solution of the given quadratic equation is x=-2 or x=-3.

To learn more about the quadratic equation visit:

brainly.com/question/2263981.

#SPJ1

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A bookmark is shaped like a rectangle with a semicircle attached at both ends. The rectangle is 17 cm
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Answer:

80.56

Step-by-step explanation:

To find the rectangle area you just multiply its length by its width:

17 * 4 = 68

You have to sum two semicircles on top of that. Since it is 2 semicircles you can just calculate one circle. Using the circle area formula:  \pi*r^2

Since the radius (r) is 2 and \pi is 3.14, you have the following equation:

A = 3.14 * 2² ==>      A = 3.14 * 4   ==>   A = 12.56     <em>(A is Area)</em>

Sum the rectangle's area with the circle's area:

12.56 + 68 = 80.56

And vuoila! there's your answer.

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Given ABCD is a parallelagram diagonals AC and BD intersect at E Prove AE is congruent to CE and BE is congruent to DE
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In the parallelogram ABCD, diagonals AC and BD intersect at point E.

According to the definition of parallelogram, opposite sides are equal and parallel to each other. That means, AB = DC

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That means, AE = CE and BE = DE

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3 years ago
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