Answer:
yes; yes
Explanation:
Phases of the moon refers to the shapes of the moon due to the lit part of it visible from the Earth. On a new moon day, the moon comes between the sun and the earth such that the lit portion is not visible from the Earth. On a full moon day, the earth comes between the sun and the moon and the whole lit part is visible.
When one would view the earth from the moon, the earth would also be visible as going through the phases. The order would be reversed. Understand this with the following example, On a new moon day, the Earth would be visible completely lit from the moon. So it will be full Earth day on the moon. On a full moon day, the lit side of the Earth would be completely away and hence, from the moon, new earth would be there.
Answer:
glucose + oxygen -> carbon dioxide + water + energy
Explanation:
The chemical equation for aerobic respiration is C6H12O6 + 6O2 → 6CO2 + 6H2O (glucose + oxygen -> carbon dioxide + water). It also produces energy.
Answer:
See explanations below
Explanation:
1) KE = 1/2mv²
mass m = 0.142kg
v = 40m/s
KE = 1/2 * 0.142 * 40^2
KE = 1/2 * 0.142 * 1600
KE = 800*0.142
KE = 113.6Joules
2) KE = 1/mv^2
KE = 196
mass m = ?
velocity v = 52m/s
Substitute
196 = 1/2*m*52²
196 = 1352m
m = 196/1352
m = 0.145kg
Hence the mass of the baseball is 0.145kg
3) KE = 1/2mV^2
288 = 1/2 * 4v²
288 = 2v²\
v² = 288/2
v² = 144
v = 12m/s
The velocity of the shotput is 12m/s
Here we have a circular motion. In that type of motion two new forces appear: centrifugal and centripetal. Centrifugal force tries to move object away frome the center of rotation. Centripetal force is the reason why object moves in a circle.
According to Newton's first law, in order for water not to spill out total force acting on water must be equal to zero. Forces acting on the water are gravitational and centrifugal.
![0= F_{g} + F_{c} \\ - [tex]F_{g} = F_{c} \\ m*g= \frac{m* v^{2} }{r} \\ g= \frac{ v^{2} }{r} \\ v^{2} =g*r \\ v= \sqrt{g*r} \\ v= \sqrt{9.81*0.95} \\ v= \sqrt{9.3195} \\ v=3.1 m/s](https://tex.z-dn.net/?f=0%3D%20F_%7Bg%7D%20%2B%20F_%7Bc%7D%20%20%5C%5C%20-%20%5Btex%5DF_%7Bg%7D%20%3D%20F_%7Bc%7D%20%5C%5C%20m%2Ag%3D%20%5Cfrac%7Bm%2A%20v%5E%7B2%7D%20%7D%7Br%7D%20%20%5C%5C%20g%3D%20%5Cfrac%7B%20v%5E%7B2%7D%20%7D%7Br%7D%20%5C%5C%20%20v%5E%7B2%7D%20%3Dg%2Ar%20%5C%5C%20%20v%3D%20%5Csqrt%7Bg%2Ar%7D%20%20%5C%5C%20v%3D%20%5Csqrt%7B9.81%2A0.95%7D%20%20%5C%5C%20v%3D%20%5Csqrt%7B9.3195%7D%20%20%5C%5C%20v%3D3.1%20m%2Fs)
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Forces have opposite signs as they act in opposite directions. But their value is the same so we can ignore signs:
