Explanation:
Given that,
Diameter of the wheel, d = 70 cm = 0.7 m
Initial angular speed, 
Final angular speed, 
Time, t = 4 s
(a) Angular acceleration,

(b) Tangential acceleration is :
Angular speed of the wheel after 2 seconds is :

Radial acceleration will be :

Hence, this is the required solution.
Answer: h = 3R
Explanation:
Using the law of conservation of energy,
Total energy at the beginning of the launch would be equal to total energy at any point.
kinetic energy + gravitational potential energy = constant
Initial energy of the projectile =
... (1)
where R is the radius of the Earth, M is the mass ofthe Earth, m is the mass of the projectile.
escape velocity, 
Total energy at height h above the Earth where speed of the projectile is half the escape velocity:
...(2)
(1)=(2)
⇒
⇒
⇒
⇒
⇒h = 3R
Thus, at height equal to thrice radius of Earth, the speed of the projectile would reduce to half of escape velocity.
Explanation:
Below is an attachment containing the solution.