Which biom ha hot days, cool nights, and very few plants

You have decided to study the effect of loud noise on plant growth. You put one plant in a quiet room and the other plant in you

Aleksandr [31]

B. control

also known as constant

7 0

3 years ago

Knowing the causes of respiratory system diseases, what are

Kamila [148]

Cover your cough
Wash your hands
Keep a clean space
Avoid smoking
Stay active

Hope this helps :)

8 0

3 years ago

3

Misha Larkins [42]

Hi there!

The maximum deformation of the bumper will occur when the car is temporarily at rest after the collision. We can use the work-energy theorem to solve.

Initially, we only have kinetic energy:

$KE = \frac{1}{2}mv^2$

KE = Kinetic Energy (J)
m = mass (1060 kg)
v = velocity (14.6 m/s)

Once the car is at rest and the bumper is deformed to the maximum, we only have spring-potential energy:

$U_s = \frac{1}{2}kx^2$

k = Spring Constant (1.14 × 10⁷ N/m)

x = compressed distance of bumper (? m)

Since energy is conserved:

$E_I = E_f\\\\KE = U_s\\\\\frac{1}{2}mv^2 = \frac{1}{2}kx^2$

We can simplify and solve for 'x'.

$mv^2 = kx^2\\\\x = \sqrt{\frac{mv^2}{k}}$

Plug in the givens and solve.

$x = \sqrt{\frac{(1060)(14.6^2)}{(1.14*10^7)}} = \boxed{0.0198 m}$

3 0

2 years ago

A cheetah can accelerate from rest to a speed of 21.5 m/s in 6.75 s. What is its acceleration? m/s^2

grandymaker [24]

Answer:

Acceleration will be $a=3.185m/sec^2$

Explanation:

We have given final velocity v = 21.5 m/sec

Time t = 6.75 sec

As cheetah starts from rest so initial velocity u = 0 m/sec

From first equation of motion we know that v = u+at, here v is final velocity, u is initial velocity, a is acceleration and t is time

So $21.5=0+a\times 6.75$

$a=3.185m/sec^2$

6 0

3 years ago

Read 2 more answers

How much heat is given off when 210.0g of water at 0 degrees freezes into ice?

Sergio [31]

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

<h3>What is freezing?</h3>

It is a physical change in which liquids give off heat to form solids.

We have 210.0 g of water at 0°C. We can calculate the amount of heat given off when it freezes into ice using the following expression.

Q = ΔH°fus × m

Q = 0.334 kJ/g × 210.0 g = 70.1 kJ

where,

Q is the heat released.
ΔH°fus is the latent heat of fusion.
m is the mass.

In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.

Learn more about freezing here: brainly.com/question/40140

#SPJ1

5 0

2 years ago