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3 years ago

14

Which biom ha hot days, cool nights, and very few plants

1 answer:

alekssr [168]3 years ago

5 0

A.Desert hope this helps

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Look at the image of a salad with chicken on a counter top .in which direction is the thermal energy moving?

mars1129 [50]

Answer:

Well,

Explanation:

In this image, the thermal energy could be going both in an upwards and downwards direction. The chicken passes thermal energy to the salad under it. But at the same time, it is releasing smoke upwards, meaning it is also releasing thermal energy upwards.

<h2>#learnwithbrainly</h2>

5 0

3 years ago

What is the first law of gravity??

neonofarm [45]

Answer:

every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

Explanation:

6 0

3 years ago

La resultante de dos fuerzas perpendiculares aplicadas a un mismo cuerpo es 11.18 N y el módulo de una de ellas es de 10 N. ¿Cuá

Dmitrij [34]

Answer:

English?

Explanation:

3 0

3 years ago

Astronauts are trained for take-off in a high-speed centrifuge of 4.7 m radius that spins in the horizontal plane.

Leokris [45]

Answer:

a) $1.94 \frac{rad}{s}$

b) $9.12\frac{m}{s}$

c) Towards the center of the centrifuge

Explanation:

a)

Becuse the centrifuge rotates in circular motion, there's an angular acceleration tha simulates high gravity accelerations

$a_{rad}=\omega r^{2}$

with r the radius and ω the amgular velocity, in or case $a_rad=3.5g$ so:

$3.5g=\omega r^{2}$ and g=9.8 $\frac{m}{s^{2}}$

solving for ω:

$\omega=\frac{3.5g}{r^2}=\frac{3.5*9.8}{4.2^2}$

$\omega = 1.94 \frac{rad}{s}$

b) Linear speed (v) and angular speed are related by:

$v=\omega r =(1.94)(4.7)$

$v= 9.12\frac{m}{s}$

c) The apparent weigth is pointing towards the center of the circle, becuse angular acceleration is pointing in that direction.

8 0

3 years ago

Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?

tester [92]

Answer: $40\ N/C$

Explanation:

Given

Magnitude of charge is $q=0.5\ C$

Force experienced is $F=20\ N$

Electric field intensity is the electrostatic force per unit charge

$\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C$

Thus, the electric field intensity is $40\ N/C$

6 0

3 years ago