If the object is completely submerged at that time, then the volume of
the full object is 652 cm³.
If only part of the object is in the water, then the volume of the part that's
in the water is 652 cm³, but we have no idea what its full volume is.
Answer:
as
- Mass of sun > Mass of earth
Therefore, the sun will exert more gravitational force on earth.
Explanation:
While comparing the gravitational force exerted by two objects, we need to observe which object has a greater mass.
- The object with the greater mass exerts a more gravitational force on the other object.
We know that mass of the sun is about 1.99 x 10³⁰ kg, and the earth's mass is only 6.0 x 10²⁴.
as
- Mass of sun > Mass of earth
Therefore, the sun will exert more gravitational force on earth.
<span>sound waves are a type of wave sometimes called compression waves, vibrations with enough of an amplitude can compress and decompress the air adjacent to the object causing the waves to form.</span>
Answer:
2.726472 s more or 1.5874 times more time is taken than 10-lb roast.
Explanation:
Given:
- The cooking time t is related the mass of food m by:
t = m^(2/3)
- Mass of roast 1 m_1 = 20 lb
- Mass of roast 2 m_2 = 10 lb
Find:
how much longer does a 20-lb roast take than a 10-lb roast?
Solution:
- Compute the times for individual roasts using the given relation:
t_1 = (20)^(2/3) = 7.36806 s
t_2 = (10)^(2/3) = 4.641588 s
- Now take a ration of t_1 to t_2, to see how many times more time is taken by massive roast:
t_1 / t_2 = (20 / 10)^(2/3)
- Compute: t_1 / t_2 = 2^(2/3) = 1.5874 s
- Hence, a 20-lb roast takes 1.5874 times more seconds than 10- lb roast.
t_2 - t_1 = 2.726472 s more
Answer:
It will take 0.01 s or 10 ms
Solution:
As per the question:
Length of the packet, L = 1,000 bytes = 
Distance, d = 2500 km = 
Speed of propagation, s = 
Transmission rate, R = 2 Mbps
Now,
Propagation time, t can be calculated as:
t = 10 ms
- In general, propagation time, t is given by:
- No, this delay is independent of the length of the packet.
- No, this delay is independent of the rate of transmission.
