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1 year ago

Tennis balls experience a large drag force. A tennis ball is hit so that it goes up and then comes back straight down.

1 answer:

8 0

A tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.

<h3>How object move upward and downward?</h3>

We know that objects move upward due to application of force on it while on the other hand, object comes to the ground because of the attraction of earth which we called gravity.

So we can conclude that a tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.

Learn more about force here: brainly.com/question/12970081

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With Christmas lights wired in series, if one light goes out, what happens to the rest?

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Answer:

The ones that are after the light that went out are also out.

Explanation:

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2 years ago

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In Example 2.12, two circus performers rehearse a trick in which a ball and a dart collide. Horatio stands on a platform 6.4 m a

pickupchik [31]

Answer:

time of collision is

t = 0.395 s

$h = 5.63 m$

so they will collide at height of 5.63 m from ground

Explanation:

initial speed of the ball when it is dropped down is

$v_1 = 0$

similarly initial speed of the object which is projected by spring is given as

$v_2 = 16.2 m/s$

now relative velocity of object with respect to ball

$v_r = 16.2 m/s$

now since we know that both are moving under gravity so their relative acceleration is ZERO and the relative distance between them is 6.4 m

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$6.4 = 16.2 t$

$t = 0.395 m$

Now the height attained by the object in the same time is given as

$h = v_2 t - \frac{1}{2}gt^2$

$h = 16.2(0.395) - \frac{1}{2}(9.81).395^2$

$h = 5.63 m$

so they will collide at height of 5.63 m from ground

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2 years ago

A student conducts an experiment in which a cart is pulled by a variable applied force during a 2 s time interval. In trial 1, t

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Answer:

The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".

Explanation:

Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.

Let's look at the speed of the car

$F = m a\\\\a =\frac{F}{m}$

We use movies and find lips

$\to v = v_0 + a t\\\\\to v = v_0 + (\frac{F}{m}) t$

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The moment change

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Let's replace the speeds in this equation

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They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.

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2 years ago

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