Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
In a store, perhaps. People want it to be easy to shop, so it would be best for say, a top ramen package to be the same net weight as all the other top ramen packages. This makes it 1) easy to label and 2) easy to be confident buying, as it is exactly the same as all the others.
The answer to this is 720000
Answer:
x=84
Step-by-step explanation:
Add 4 on both sides
3=x/12-4
7=x/12
Multiply both sides by 12
(12)7=x/12(12)
84=x
Hope this helps! :)
Answer:
57 and a remainder of 1 or 0.11.
Step-by-step explanation:
514dividedby9=57.1
