X^2+6x+8=0 To write the above in the form of (x-p)^2=q we proceed as follows: i] Re-write the expression: x^2+6x=-8 ii] Calculate for the vale of c. c=(b/2a)² given that: b=6, and a=1 thus c=(6/2*1)^2=9
iii] Add 9 on both sides of the equation from i x^2+6x+9=-8+9 simplifying we get: x^2+6x+9=1 factoring the LHS we get: (x+3)(x+3)=1 (x+3)²=1 The above is in the form of: (x-p)²=q where: p=3 and q=1
