This is similar to the other question you posted. Follow the same steps as before.
First find g(41).
g(41) = sqrt{x - 5}
g(41) = sqrt{41 - 5}
g(41) = sqrt{36}
g(41) = 6
We now find f(6).
f(6) = -7(6) + 1
f(6) = -42 + 1
f(6) = -41
Answer:
(fºg)(41) = -41
Did you follow?
Answer:
I need some more context
Step-by-step explanation:
Answer:
one solution, no solution, infinitely many solutions
Step-by-step explanation:
I rearranged the first equation into x=6-2y
plug that into the second equation
2(6-2y)-3y=26
12-4y-3y=26
12-7y=26
-7y=14
y=-2
Then you plug that into one of the equations
x+2(-2)=6
x-4=6
x=10
The solution to the first system is (10,-2)
the second system already has one equation as something equal to a single variable so you just plug that into the other one
4x-2(2x-4)=-6
4x -4x +8 =-6
8=-6
this is a false statement so the system of equation has no solution
Lastly I rearranged the first equation into y=2x-4 and then plug that in
6x-3(2x-4)=12
6x-6x+12=12
12=12
this statement is true so the system of equations has infinite solutions
To find surface area, find the area of the net like you would for a composite figure.
For the square, area is length times width.
8*8=64
For the triangles, area is bh/2
8*8/2=32
Since there are four triangles of the same area, multiply by 4.
32*4=128
Add these values
128+64=192 cm^2
Final answer: D
Get the app Photomath to do basic math like this, otherwise:
First flip the reciprocal - (-5/8) changes to (8/5).
Next reduce, the 5's change to 1, and the 12 and 8 leave it as...
(1/3) x 2 =
(2/3) As your answer
