A very small dinosaur , the microraptor was only 1.3 feet long. one of the largest dinosaures the diplodocus was about 91 feet long. how many times as long as the microraptor was the diplodocus ? =78 feet
Can you tell me what you need help because it doesn't says
Answer:
10x
Step-by-step explanation:
Answer:
Great work!
Step-by-step explanation:
These kind of questions are calculated through Riemann Sum. You can evaluate any definite integral using the Riemann Sum. It should be in the following form:
f(x)dx on the interval [a, b], or
Now f(x) is simply y. Therefore in this example y = x^3 - 6x. We just need the sufficient amount of data to apply the Riemann Sum, including the interval [a, b] that bounds the area, and the the number of rectangles 'n' that we need to use.
Consider an easier approach to this question: (First attachment)
Graph: (Second Attachment)