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Airida [17]
2 years ago
11

5. What's true of the distribution of any variable, if your model is the mean of that variable? A The distribution of the variab

le is more narrow than the distribution of its residual. The distribution of the variable is more narrow than the distribution of its residual. B The distribution of the variable is always centered on a number lower than the distribution of the residual is centered on. The distribution of the variable is always centered on a number lower than the distribution of the residual is centered on. C The distribution of the variable is always centered on 0, whereas the center of the distribution of its residual is unpredictable. The distribution of the variable is always centered on 0, whereas the center of the distribution of its residual is unpredictable. D The distribution of the variable is the same shape as the distribution of its residual
Mathematics
1 answer:
Alex2 years ago
6 0

The true statement about the distribution of any variable model around the mean is (D) The distribution of the variable is the same shape as the distribution of its residual

<h3>The true statement about the distribution</h3>

From the question, we understand that the distribution of the model is based on its mean or average value.

The above means that the upper and the lower deviations are balanced.

Hence, the true statement about the distribution of any variable model around the mean is (D)

Read more about distribution at:

brainly.com/question/15713806

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A tank contains 30 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min
Dmitry [639]

At any time t (min), the volume of solution in the tank is

500\,\mathrm{gal}+\left(5\dfrac{\rm gal}{\rm min}-5\dfrac{\rm gal}{\rm min}\right)t=500\,\mathrm{gal}

If A(t) is the amount of salt in the tank at any time t, then the solution has a concentration of \dfrac{A(t)}{500}\dfrac{\rm lb}{\rm gal}.

The net rate of change of the amount of salt in the solution, A'(t), is the difference between the amount flowing in and the amount getting pumped out:

A'(t)=\left(5\dfrac{\rm gal}{\rm min}\right)\left(\left(2+\sin\dfrac t4\right)\dfrac{\rm lb}{\rm gal}\right)-\left(5\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{A(t)}{50}\dfrac{\rm lb}{\rm gal}\right)

Dropping the units and simplifying, we get the linear ODE

A'=10+5\sin\dfrac t4-\dfrac A{10}

10A'+A=100+50\sin\dfrac t4

Multiplying both sides by e^{10t} allows us to identify the left side as a derivative of a product:

10e^{10t}A'+e^{10t}A=\left(100+50\sin\dfrac t4\right)e^{10t}

\left(e^{10}tA\right)'=\left(100+50\sin\dfrac t4\right)e^{10t}

e^{10t}A=\displaystyle\int\left(100+50\sin\dfrac t4\right)e^{10t}\,\mathrm dt

Integrate and divide both sides by e^{10t} to get

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+Ce^{-10t}

The tanks starts off with 30 lb of salt, so A(0)=30 and we can solve for C to get a particular solution of

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+\dfrac{32,220}{1601}e^{-10t}

6 0
3 years ago
&lt;1 and &gt;2 are &lt;2 has a measure of 108 what is the measure of &lt;1
antoniya [11.8K]

Answer:

If these two are supplementary angles, than <1 is 72 degrees.

Step-by-step explanation:

In order to find that, we simply need to subtract the first angle from 180 degrees.

180 - 108 = 72 degrees

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3 years ago
Find the slope of line passing through {-7,-6} and {5, -6}
suter [353]

Answer:

slope=(y2-y1)/(x2-x1)

where (x1,y1)=(-7,-6)

(X2,y2)=(5,-6)

slope=(-6+6)/(5+7)=0

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3 years ago
Jean drove 70 miles per hour for a total of 420 miles on a trip. She used the equation below to calculate the time, t, it would
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Answer:

D because she is constantly going 70 MPH

Step-by-step explanation:

hope this helps

8 0
3 years ago
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Simplify the expression by using the distributive property 2(3x-5)​
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Step-by-step explanation:

multiply the outer term to the inner term

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