I think You should break it down to the First and third One because of
Answer:
Step-by-step explanation:
I see you're in college math, so we'll solve this with calculus, since it's the easiest way anyway.
The position equation is
That equation will give us the height of the rock at ANY TIME during its travels. I could find the height at 2 seconds by plugging in a 2 for t; I could find the height at 12 seconds by plugging in a 12 for t, etc.
The first derivative of position is velocity:
v(t) = -3.72t + 15 and you stated that the rock will be at its max height when the velocity is 0, so we plug in a 0 for v(t):
0 = -3.72t + 15 and solve for t:\
-15 = -3.72t so
t = 4.03 seconds. This is how long it takes to get to its max height. Knowing that, we can plug 4.03 seconds into the position equation to find the height at 4.03 seconds:
s(4.03) = -1.86(4.03)² + 15(4.03) so
s(4.03) = 30.2 meters.
Calculus is amazing. Much easier than most methods to solve problems like this.
Answer:
-83/51
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
The expression is
x^2 - 4
This is a quadratic expression.
To find the solution, we will equate the the expression to zero. It becomes
x^2 - 4 = 0
Add 4 to the left hand side of the equation and the right hand side of the equation. It becomes.
x^2 - 4 + 4 = 0 + 4
x^2 = 4
Take square root of the right hand side of the equation and left hand side of the equation. It becomes
√x^2 = √4
x = ± 2
x = 2 or x = - 2