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Sunny_sXe [5.5K]
3 years ago
5

Free point lang po 50cliam lang po ty​

Mathematics
2 answers:
BabaBlast [244]3 years ago
5 0

i dont want to lie but umkm i really need points right now sorry

Sever21 [200]3 years ago
3 0

Answer:

thankyou for points

don't waste your points

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The formula to get the area of a circle is: A = πr²

  • Area = pi × radius²
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1/3 multiplied by 1 1/2
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0.5

Step-by-step explanation:

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3 years ago
Which completely describes the polygon
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3 years ago
If the factors of function f are (x - 6) and (x - 1), what are the zeros of function f?
lidiya [134]
X=6 and x=1

You can find your zeros by determining what you have to plug into the function in order for it to equal zero

If we plug in 6, for example we’d get (6-6)(x-1)

Simplified this is 0(x-1)

Anything times 0 is 0, so this is one of our zeros.

Same goes for x-1, we just need to plug in 1 for it to equal 0

Therefore there are zeros at x=1 and x=6 :))
7 0
3 years ago
In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=
just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements:                                                           Reasons:

\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}      Given

\displaystyle 2) \text{ } m \angle PAB = 60                                                     Definition of equilateral.

3)\text{ } m \angle QAC = 60                                                     Definition of equilateral.

4)\text{ } m\angle PAB = m\angle QAC                                          Substitution

5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC                       Angle Addition

\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC                       Angle Addition

7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC                       Substitution

\displaystyle 8)\text{ } m\angle PAC=m\angle QAB                                         Substitution

9)\text{ } PA=BA                                                          Definition of equilateral

10)\text{ } AC=AQ                                                        Definition of equilateral

\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ                                            Side-Angle-Side Congruence*

\displaystyle 12)\text{ } PC=BQ                                                        CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

6 0
3 years ago
Read 2 more answers
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