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3 years ago

John types 62 words per minute. Which an expression for the number of words he types in m minutes?

Mathematics

1 answer:

andrezito [222]3 years ago

8 0

Answer:

w = 62m

Step-by-step explanation:

We need to make an expression for the numbers of words (w) John types in m minutes.

We know he types 62 words in 1 minute, so 62 is the coefficient of m.

The dependent variable here is w, so that should on the left of the equal sign.

m, on the other hand, is independent, so that's on the right of the equal sign.

So, the expression is w = 62m.

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1 year ago

How many miles can you drive in 1/2 hour

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Answer:

2 miles

Step-by-step explanation:

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2 years ago

What is the equation of the line in slope-intercept form

vagabundo [1.1K]

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-2

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as x goes up 1 y goes down 2

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3 years ago

ALG 2<br> 7x+y=9<br> solve for y

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7x+y-9=0

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3 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

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2 years ago