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Soloha48 [4]
3 years ago
5

Are two obtuse triangles always, sometimes, or never similar

Mathematics
2 answers:
NeTakaya3 years ago
5 0

if two triangles are similar then they are congruent

aksik [14]3 years ago
4 0

Answer:

My Answer Is ALWAYS.

Why I Think So:

<u>It's Because As You Said...They Have Obtuse Angle, Which Can Never Change.</u>

You might be interested in
Equation Given: <img src="https://tex.z-dn.net/?f=h%28t%29%3D-4.9t%5E%7B2%7D%2B358" id="TexFormula1" title="h(t)=-4.9t^{2}+358"
Vilka [71]

Answer:

At 3.44 seconds, the penny is at a height of 300 meters above the ground.

Step-by-step explanation:

Basically, we have to solve an equation here:

-4.9t^{2} + 358 = 300

Hence,

-4.9t^{2} = 300 - 358

t^{2} = \frac{-58}{-4.9}

t = 3.44

Hence, at 3.44 seconds, the penny is at a height of 300 meters above the ground.

Hope this helped!

4 0
2 years ago
10 POINTS!!! FULL ANSWER WITH FULL STEP BY STEP SOLUTION PLEASE. DO BOTH PARTS OF 1 AND ALL OF 2.
diamong [38]
One A
y = e^x
dy/dx = e^x The f(x) = the differentiated function. Any value that e^x can have, the derivative has the same value. x is contained in all the reals.
One B
y = x*e^x
y' = e^x + xe^x Using the multiplication rule.
You want the slope and the value of the of y to be the same. The slope is y' of the tangent line
xe^x = e^x + xe^x
e^x = 0
This happens only when x is very "small" like x = - 4444444

y = e^x * ln(x) Using the multiplication rule again, we need the slope of the line with is y'
y1 = e^x
y1' = e^x
y2 = ln(x)
y2' = 1/x
y' = e^x*ln(x) + e^x/x So at x = 1 the slope of the line = 
y' = e^1*ln(1) + e^1/1
y' = e*0+e  = e
y = mx + b
y = ex + b
to find b we use y= e^x ln(x)

e^x ln(x) = e*x + b
e^1 ln(1) = e*1 + b
ln(1) = 0
0 = e + b
b = - e

line equation and answer.
y = e*x - e
8 0
3 years ago
I solved 4, the answer is 11, seconds: 5x+4(x-3)=87 = x=11, but I don't know how to solve number 5, please anyone explain how to
liq [111]

The answer x = 11 is correct for problem 4. Nice work.

Use this x value to find the answer in problem 5. From problem 4, we're told that Romeo runs at a speed of 5 m/s. If he runs for x = 11 seconds,then he runs a total distance of:

5*x =(5 m/s)*(x meters) = (5 m/s)*(11 seconds) = 5*11 = 55 meters

The answer to problem five is 55 meters

8 0
3 years ago
How do I solve this?
Delvig [45]

Answer:

10a + 2b

Step-by-step explanation:

Add the lengths of all sides:

3a + b + b + 2a - b + 3a + b + b + 2a - b

Now combine like terms:

10a + 2b

4 0
3 years ago
Unit rate feet per second 180 miles over 2 hours
Tatiana [17]
So that is equal to 180 miles per 2 hours which is 90 miles per hour if each hour has the same m/hr rate.
You can set up a proportion:
let x = number of miles per hour
\frac{x}{180} = \frac{1}{2}
cross multiply and you get
2x=180
divide both sides by 2 and you get
x=90
so you get the same answer both ways,
90 miles per hour
5 0
3 years ago
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