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lions [1.4K]
3 years ago
6

Find all the factor pairs for 84 and complete the equations.

Mathematics
1 answer:
VMariaS [17]3 years ago
5 0
1. 84 = 1 x 84

2. 84 = 2 x 42

3. 84 = 3 x 28

4. 84 = 4 x 21

5. 84 = 6 x 14

6. 85 = 7 x 12


Hope this helps!
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Let a and b be non-zero integers
r-ruslan [8.4K]

Answer:

The correct answer is d

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Please help me please please : ( : (
Gala2k [10]

Answer:

They will be picked up at 2 \frac{1}{4} yards above sea level

Step-by-step explanation:

Let us consider sea level as reference and positions above sea level as positive and below sea level as negative.

With respect to this reference,

the position of top most point is +17 \frac{3}{4} yards

and the position of lower most point is -13 \frac{1}{4} yards

⇒ The position of midpoint is \frac{+17 \frac{3}{4} - 13 \frac{1}{4}}{2}

                                              = +2 \frac{1}{4}

∴ <u>They will be picked up at 2 \frac{1}{4} yards above sea level</u>

6 0
3 years ago
The circumference of a circle is 6π m. What is the area, in square meters? Express your answer in terms of \piπ.
zaharov [31]

Answer:

Area = 9π sq. m.

Step-by-step explanation:

C = πd

6π = πd

d = 6

r = 3

A = πr^{2} = π3^{2} =  9π sq. m.

5 0
2 years ago
A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading
Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

b.

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0
3 years ago
HELP I REALLY NEED HELP
zepelin [54]

Answer: 72 inches squared

Step-by-step explanation:

So, the real floor of a classroom is 36 feet by 32 feet.

And the scale drawing, has length of the classroom equal to 9 inches.

What is the area in square inches of the floor in the scale drawing

1 foot = 12 inches

The length of the classroom, measured in feet, has been multiplied by 12, to get converted in inches. After that, it has been divided by a number, a proportion, to get to 9 inches.

36feet * 12 / x = 9 inches

432 inches / x = 9 inches

Now, to solve for x, we can cross-multiply

432 inches = 9x inches

Divide 9 inches on both sides.

x = 48

To solve the exercise, we need to calculate the floor's area in the scale drawing.

We have the length = 9 inches.

Now, let's calculate the width

Width = 32 feet * 12 / 48

Width = 384 inches / 48

Width = 8 inches

Area = Length * Width

Area = 9 inches * 8 inches

Area = 72 inches squared

Hope I helped!

6 0
2 years ago
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