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babymother [125]
2 years ago
6

3. x² +(y + 2)2 = 64 Center: Radius:

Mathematics
2 answers:
MariettaO [177]2 years ago
8 0

Answer:

Step-by-step explanation:

Center: (0, -2)

Radius: √64 = 8

harkovskaia [24]2 years ago
5 0

Answer:

Center: (0, -2)

radius: 8

Explanation:

<u>Given equation</u>: x² + (y + 2)² = 64

The Circle Formula:

(x - h)² + (y - k)² = r²

where (h, k) are points of center. r denotes radius

So rewrite the equation in circle formula:

x² +(y + 2)² = 64

(x- 0)² +(y + 2)² = 8²

Identify followings:

h = 0, k = -2, radius = 8

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PLS HURRY DOUBLE-CHECKING<br><br>what is: 94 ÷ 17​
maxonik [38]

Answer:

94/17=5.5294

Step-by-step explanation:

that's what I got

8 0
2 years ago
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G(x) = -2x^3 – 15x^2 + 36x
shusha [124]

Consider the function G(x) = -2x^3 - 15x^2 + 36x. First, factor it:

G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).

The x-intercepts are at points \left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).

1. From the attached graph you can see that

  • function is positive for x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);
  • function is negative for x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).

2. Since

G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x) the function is neither even nor odd.

3. The domain is x\in (-\infty,\infty), the range is y\in (-\infty,\infty).

8 0
3 years ago
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What is the decimal value of the fraction 2/7 ? 0.285714¯ 0.285714¯¯¯¯¯¯¯¯¯¯ 0.2857142857¯¯¯¯¯ 0.285714
Leviafan [203]
The decimal of the fraction 2/7 is 0.2857142857
4 0
3 years ago
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Can someone solve and explain this question plz​
oee [108]

firstly let's convert the mixed fraction to improper fraction, then hmmm let's see we have two denominators, 5 and 3, and their LCD will simply be 15, so we'll multiply both sides by that LCD to do away with the denominators, let's proceed,

\bf \stackrel{mixed}{2\frac{1}{3}}\implies \cfrac{2\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{7}{3}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{z}{5}-4=\cfrac{7}{3}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{15}}{15\left( \cfrac{z}{5}-4 \right)=15\left( \cfrac{7}{3} \right)}\implies 3z-60=35 \\\\\\ 3z=95\implies z=\cfrac{95}{3}\implies z = 31\frac{2}{3}

4 0
3 years ago
Choose a system of equations with the same solution as the following system:
Lina20 [59]

Answer:

Option A.

Step-by-step explanation:

We are given 6x+2y =-6 ......(1) and 3x-4y=-18 .....(2)

Solving equations (1) and (2) we get

12x+3x =-30, ⇒x= -2 and from equation (1), 2y= -6-6(-2) =6, ⇒ y=3

Therefore, the solution for the given set of equations is x= -2 and y=3

A) Solving the equations 8x+4y = -4 ....... (3)and 17x+2y =-28, we get  

8x -34x = -4 -(-56) =52, ⇒-26x =52, ⇒x=-2 and from equation )(3), we get -16+4y =-4, ⇒ y=3

Therefore, the solution x=-2 and y =3 match with the original solution.

B)Solving the equations 12x + 4y = 12 ....... (4)and 21x + 2y = −36, we get  

12x -42x = 12 -(-72) =84, ⇒-30x =84, ⇒x=-84/30.

Therefore, the solution x=-84/30 does not match with the original solution.

C) Solving the equations 6x + 8y = −36 ....... (4) and 15x + 6y = −60, we get 18x -60x = -108 -(-240) =132, ⇒-42x =132, ⇒x=-132/42

Therefore, the solution x=--3  do not match with the original solution.

D) Solving the equations 6x + y = 15 ....... (5) and 15x − y = −9, we get 6x +15x = 6, ⇒21x =6, ⇒x=2/7  

Therefore, the solution x=2/7  do not match with the original solution.

Therefore, option A) will have the same solution. (Answer)

4 0
3 years ago
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