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Andrews [41]
3 years ago
11

A certain liquid has a density of 2.67 g/cm3. 30.5 ml of this liquid would have a mass of __________ kg.

Chemistry
1 answer:
8090 [49]3 years ago
8 0
Hey there!

Density = 2.67 g/cm³

volume = 30.5 mL

Mass = density *volume

Mass = 2.67 * 30.5

Mass = 81.435 g

Therefore:

Mass in kg :

1 kg -------------- 1000 g
?? ----------------- 81.435 g

mass = 81.435 * 1 / 1000

mass = 0.081435 kg 


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Answer:

T_2=335.42K=62.27^oC

Explanation:

Hello,

In this case, by using the general gas law, that allows us to understand the pressure-volume-temperature relationship as shown below:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Thus, solving for the temperature at the end (considering absolute units of Kelvin), we obtain:

T_2=\frac{P_2V_2T_1}{P_1V_1}=\frac{1.8L*0.75atm*(25+273.15)K}{1.2L*1.0atm} \\\\T_2=335.42K=62.27^oC

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Answer:

A.   it is the lowest at low temperatures

Explanation:

It is true with respect to the kinetic energy of a molecule that the it is the lowest at low temperatures.

The kinetic energy of a molecule is the energy due to the motion of the particles within a substance.

  • Kinetic energy is directly proportional to the temperature of a substance.
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How many moles of Mg3(PO4)2 are in 350.00 grams of Mg3(PO4)2?
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1.3 moles/ 1.33150727 moles

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<h3>Answer:</h3>

84

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3 years ago
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The solution will produce BaF₂(s) -precipitate- just when [Ba²⁺] [F⁻]² > 1.7x10⁻⁶.

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That means, when [F⁻] exceeds 0.0109M concentration, BaF₂ will precipitate

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