Is would be heat or light
<u>Answer:</u> The volume of concentrated hydrochloric acid solution is 1.73 mL
<u>Explanation:</u>
To calculate the hydrogen ion concentration of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
pH = 1.60
Putting values in above equation, we get:
![1.60=-\log [H^+]](https://tex.z-dn.net/?f=1.60%3D-%5Clog%20%5BH%5E%2B%5D)
![[H^+]=10^{-1.60}=0.0251M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-1.60%7D%3D0.0251M)
To calculate the volume of the concentrated solution, we use the equation:

where,
are the molarity and volume of the concentrated HCl solution
are the molarity and volume of diluted HCl solution
We are given:

Putting values in above equation, we get:

Hence, the volume of concentrated hydrochloric acid solution is 1.73 mL
Answer:
Explanation:
H2CO3 = H+ + HCO3- H2CO3 = 0.530 M Ka =4.4 X10^-7
Ka =[H+][A-]/[HA] [H+] = [A-]
0.530 M x 4.4 X10^-7= [H+}^2
2.32 X10^-7 = [H+}^2
23.2 X10^-8 = [H+}^2
4.83 X 10^-4 = [H+]
pH = - log 4.83 X 10^-4
pH = -(.68-4)
pH =-(-3.32)
pH= 3.32
MNaHCO₃: 23+1+12+(48×3) = 84g
mCH₃COOH: 12+(1×3)+12+(16×2)+1 = 60g
.................
84g NaHCO₃ react with 60g CH₃COOH
83g NaHCO₃ react with...........
84g ----- 60g
83g ----- X
X = 59,29g CH₃COOH
We used 70g CH₃COOH, it' too much.
So, acetic acid is excess reagent, and sodium bicarbonate is limiting reagent.
_______________________________
B) Amount of CH3COOH is in excess.
:•)