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Keith_Richards [23]
2 years ago
11

Oxidation number of Ni in Ni(CO)4 is​

Chemistry
1 answer:
nikdorinn [45]2 years ago
5 0

Answer:

0

Explanation:

answer from gauth math

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MrRa [10]

Answer:

2h+02=h20

Explanation:

2 in front of h on left side

2 in front of h on right side

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Anaerobic Cellular Respiration
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I A hole

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Look at the properties of Oxygen and Silicon - the two most abundant elements in the Earth's crust - by clicking on their symbols on the Periodic Table.

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CALCULATOR
suter [353]

Answer: The possible molecular formula will be CO_2

Explanation:

Mass of C= 27.3 g

Mass of O = 72.7 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{27.3g}{12g/mole}=2.275moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{72.7g}{16g/mole}=4.544moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{2.275}{2.275}=1

For O =\frac{4.544}{2.275}=2

The ratio of C : O = 1: 2

Hence the empirical formula is CO_2

The possible molecular formula will be=n\times CO_2

5 0
3 years ago
on dr v’s bookshelf there are 23 science textbooks each with an average of 31 chapters of each chapter contains 5 pages how many
olga55 [171]

Answer:

There are 3600 pages to 2 significant figures

Explanation:

Working only with the information given, we have that there are 23 books each with about 31 chapters.

This means that if 1 book has 31 chapter, the 23 science books will have

31 X 23 chapters =713 chapters in total.

If each chapter contains 5 pages, for the 713 chapters we will have a total of 713 X 5 pages = 3565 pages.

Rounding off the answer to 2 significant figures , we are looking to have only two non-zero figures in our answer. To do this, we count two numbers from the left. This will be numbers 3 and 5.

Next,  we check the net number after 5 to see if it is greater than 5 if it is, we will have to add the number (1 ) to the 5. This shows that we are approximating upwards, to account for the fact that that number has passed the middle point.

After this, we change the remaining two numbers (6 and 5) to zeroes.

This will give us 3600 pages.

8 0
3 years ago
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