Burning of fossil fuels: when we burn fossil fuels, CO2 is produced
Respiration: when animals respire, they convert O2 to CO2 which is then released into the atmopshere
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Answer:
Linoleic acid has 18 carbons in its carbon chain and 2 double bonds, and the first double bond starts at the 6th carbon from the omega end, thus, it is named omega 6.
Explanation:
Fatty acids are carboxilic acids with long chains of carbon (always in even numbers). There are two types of fatty acids: saturated fatty acid s(without double bonds) or unsaturated fatty acids (with double bonds). Unsaturated fatty acids has common names (linolenic acid, palmitic acid, etc.) and the position of the first double bond present in the molecule are indicated with the greek letter omega (counting from the omega extreme, it means the one with metyl radical) . Based 0on that, unsaturated fatty acids are also called omega x, where "x" represents the position of the first double bond. In the present case, the fatty acid that has 18 carbons and two double bonds is commonly named as linoleic acid and taken into account the position of its first double bond (carbon 6) it is also called omega 6.
The compound that ontains the most deactivated aromatic ring is the one called Nitrogen dioxide also knwon as NO2. Let me explain a little bit more about the aromatic rings. These rings are simple aromatics, or arenes, that consist of a conjugated planar ring system. Nitrogen generally is a simple aromatic ring that can be heterocyclic because containsnon-carbon ring atoms. The rings of the nitrogen can be separated into basic aromatic rings and that is why this ompound is also refered as a deactivated aromatic ring.
Answer:
5.01%
Explanation:
Density of vinegar = mass/volume
Mass of 10.00 mL = density x volume
= 1.006 x 10 = 10.06 g
From the equation of reaction:
1 mole pf CH3COOH requires 1 mole of NaOH for neutralization.
mole of NaOH = molarity x volume
= 0.5062 x 0.01658
= 0.008392796 mole
0.008392796 mole of NaOH will therefore require 0.008392796 mole of CH3COOH.
mass of CH3COOH = mole x molar mass
= 0.008392796 x 60.052
= 0.504 g
Percentage by mass of acetic acid in the vinegar = 0.504/10.06 x 100%
= 5.01%
The percent by mass of acetic acid in the vinegar is 5.01%