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lutik1710 [3]
3 years ago
15

On the previous problem, you found a unit rate of ounces per box. Explain how you find a unit rate when given a rate.

Mathematics
2 answers:
klio [65]3 years ago
6 0

Answer:

First, I would write the rate as a fraction. Then I would divide the numerator by the denominator.

Step-by-step explanation:

this is the sample response on e2020.

Hope it helps :D

Afina-wow [57]3 years ago
3 0

Answer:

A unit rate is a rate with 1 in the denominator. If you have a rate, such as price per some number of items, and the quantity in the denominator is not 1, you can calculate unit rate or price per unit by completing the division operation: numerator divided by denominator.

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What is the simplified expression for the expression below? -1/5(5x+20)-1/4(4x-28)
e-lub [12.9K]

You need to distribute the numerical factors for each term in the parenthesis:

\dfrac{-1}{5}(5x+20)-\dfrac{1}{4}(4x-28) = \dfrac{-1}{5}\cdot 5x + \dfrac{-1}{5}\cdot 20 + \dfrac{-1}{4} \cdot 4x + \dfrac{-1}{4} \cdot (-28)

This equals

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3 years ago
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The temperature, T, of a given mass of gas varies inversely with its Volume,V. The temperature of 98 cm ³ of a certain gas is 28
Naily [24]

Answer:

T₂ = 421.4 K

Step-by-step explanation:

The temperature, T, of a given mass of gas varies inversely with its Volume,V.

T\propto \dfrac{1}{V}\\\\V_1T_1=V_2T_2

We have,

V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K

V₂ = 70 cm₃

We need to find the new temperature of the gas. Using the above relation to find T₂.

T_2=\dfrac{V_1T_1}{V_2}\\\\T_2=\dfrac{98\times 301}{70}\\\\T_2=421.4\ K

Hence, the required temperature of the gas is 421.4 K.

4 0
3 years ago
I need help im doing BODMAS and i dont really understand:
mars1129 [50]

Answer:

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Step-by-step explanation:

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