What is the slope for y = 4 + 3x? * Your answer

Selected accounts with a credit amount omitted are as follows: Work in Process Apr. 1 Balance 7,000 Apr. 30 Goods finished X 30

lawyer [7]

Answer:

$29,900

Step-by-step explanation:

The computation of the balance of Work in Process as of April 30 is shown below:

= Opening balance of work in process + direct material cost + direct labor cost + factory overhead cost - goods finished

= $7,000 + $78,400 + $195,000 + $136,500 - $387,000

= $29,900

The direct material cost + direct labor cost + factory overhead cost is known as manufacturing cost

3 0

3 years ago

1. - 4 + (-8) =

lara [203]

1)4-8=-4
2)3+4-5=2
3) -13
4)8+12=20
5) -14

4 0

3 years ago

Read 2 more answers

The verticles of a triangle are the points R(3,c),Q(9,2) and R(3c,11) where c is constant. Given that angle PQR is 90

IceJOKER [234]

Answer:

Step-by-step explanation:

Find c if ∠PQR = 90°?

I will ASSUME you mean point P is at (3. c)

slope of PQ is (2 - c) / (9 - 3) = (2 - c) / 6

slope of QR is (11 - 2) / (3c - 9) = 9 / (3c - 9)

perpendicular lines have negative reciprocal slopes.

(2 - c) / 6 = -1(3c - 9)/9

9(2 - c) = -6(3c - 9)

18 - 9c = -18c + 54

9c = 36

c = 4

5 0

2 years ago

I need help with #29 I really don't understand it (picture included)

Katena32 [7]

4x+4(3)+4(2)=y
4x+20=y
X equals the amount it cost for each ticket which is unknown. Y equals the total cost. Because the amount of the food is provided, it can be calculated unlike the tickets which is just left at 4x. The work for the snacks are upwards. Its mostly substitution.

6 0

3 years ago

A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar

Elenna [48]

Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ounces, with a sample standard deviation of 0.052 ounces.

Let $\mu$ = population mean amount packaged.

So, Null Hypothesis, $H_0$ : $\mu$ = 8.17 ounces {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 8.17 ounces {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount dispensed = 8.171 ounces

s = sample standard deviation = 0.052 ounces

n = sample of packages = 50

So, the test statistics = $\frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }$ ~ $t_4_9$

= 0.1359

The value of t-test statistics is 0.1359.

Also, the P-value of test-statistics is given by;

the meaning of the p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

P-value = P( $t_4_9$ > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

6 0

2 years ago