The central nervous system and the peripheral nervous system
Answer- you would use a Punnet Square to cross the kinds. In order to know which ones to use, you'd have to test them all. Without knowing what each letter codes for it is hard to show
Answer:
This experiment proved that DNA replicated semiconservatively; half the original polynucleotide is conserved in each of the two copies
Explanation:
Semi-conservative mode of replication means that the two strands of DNA unwind from each other, and each of themacts as a template for synthesis of a new, complementary strand. As a result, two formed DNA moleculesc ontain one original strand and one new strand.
Meselson and Stahl experiment showed this model by labeling the DNA of bacteria across generations using isotopes of nitrogen ( patterns of DNA labeling showed the mode of replication).
The Griffith's experiment, the Avery-MacLeod-McCarty experiment, and the Hershey–Chase experiments were the set of experiments that established DNA as the key hereditary molecule. The Avery-MacLeod-McCarty experiment was an extension to the Griffith's experiment. The heat killed virulent S strain cells of the Griffith's experiment were lysed to form a supernatant containing a mix of RNA, DNA, proteins and lipids from the cell. The supernatent was equally divided into 3 parts after the removal of the lipids. The 3 parts were respectively treated with an RNAase to degrade the RNA, DNAase to degrade the DNA and proteinase to degrade the proteins. The treated supernatant was then added into the culture containing the non-virulent R cells. In case of the supernatant treated with the DNAse, no transformation of R cells into S cells occurred. The transformation of R cells to S cells occurred in the proteinase and the RNAse cases. This indicated that DNA was the hereditary molecule and not protein or RNA.
Answer:
50 %
Explanation:
It is given that a woman gives birth to a baby boy. Her second child is also a baby boy. Now she is about to give birth to her third child. We have to determine the probability of the child to be a girl.
Here, the probability of the child to be a girl would be 50 % or 1 out of 2.
There are two possibilities and the possibilities would result a boy child or a girl child. So there are two possible outcomes and is equally likely with each child birth.
Also each child birth is an independent event, so the probability that the one results will occur do not depend on the previous births.
