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Margarita [4]
3 years ago
6

A heat engine uses thermal energy that flows from a heat source with a temperature of 325 K to a cold sink, which has a temperat

ure of 135 K. What is the efficiency of the heat engine? The answer should have three significant figures
Physics
2 answers:
Ilya [14]3 years ago
5 0
The answer is "58.5"
LuckyWell [14K]3 years ago
4 0

Answer:

58.5 %

Explanation:

temperature of hot source, T1 = 325 K

temperature of cold source, T2 = 135 K

The efficiency of a heat engine is defined as the ratio of work done to the input energy.

the formula to find the efficiency of heat engine is given by

η = 1 - T2 / T1

η = 1 - 135 / 325

η = 0.585

η = 58.5 %

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Answer:

Explanation:

the one thrown below the horizontal is going straight down, while the one above the horizontal will experience a projectile motion which will makes it move farther away from the building where it was projected.

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. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms causes many photons with the same to be continu
mrs_skeptik [129]

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same <u>wavelength </u>to be continuously emitted.

From the questions given, the main objective is to fill in the gaps and add important information where necessary. The missing information is highlighted in bold and underlined.

  1. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same <u>wavelength </u>to be continuously emitted.

    2. When these photons are emitted, they travel between two <u>reflective </u>

         surfaces to form the wave that is represented in the simulation.

    3. This wave is the summation of all the photons being introduced with

        every oscillation, and as they continue to travel, the amplitude

        <u>increases. </u>

     4.  This occurs because the photons are emitted in a coherent fashion;

        however, amplitude when the photons overlap in an incoherent

        fashion.

     5.  In a laser device, a small portion of photons are permitted to escape

          (for use in an application). This is emulated in the simulation, by

         settling the Damping to Lots such that amplitude <u>remains relatively </u>

         <u>constant </u>when compared to damping of None. (Damping

         represents the Loss of photons.

       6. The generation of multiple wavelengths is possible in some laser

           producing systems, and the diffraction angle can be <u>varied</u> to allow

          the isolation of different wavelengths.

       7. Finally, when the power of a laser is described, the wave property

          that is being referenced is a function of its frequency and

          <u>amplitude.</u>

Therefore, we can conclude that we've fully understood the concept of emission of photons and wavelength in a laser apparatus.

Learn more about wavelength here:

brainly.com/question/23023103?referrer=searchResults

5 0
3 years ago
Before beginning a long trip on a hot day, a driver inflates anautomobile tire to a gauge pressure of 2.70 atm at 300 K. At the
anygoal [31]

Answer:

The value is the temperature of the air inside the tire T_{2} = 340.54 K

% of the original mass of air in the tire should be released 99.706 %

Explanation:

Initial gauge pressure = 2.7 atm

Absolute pressure at inlet P_{1} = 2.7 + 1 = 3.7 atm

Absolute pressure at outlet P_{2} = 3.2 + 1 = 4.2 atm

Temperature at inlet T_{1} = 300 K

(a) Volume of the system is constant so  pressure is directly proportional to the temperature.

\frac{T_{2} }{T_{1} } = \frac{P_{2} }{P_{1} }

\frac{T_{2} }{300}  = \frac{4.2}{3.7}

T_{2} = 340.54 K

This is the value is the temperature of the air inside the tire

(b). Since volume of the tyre is constant & pressure reaches the original value.

From ideal gas equation P V = m R T

Since P , V & R is constant. So

m T = constant

m_{1}  T_{1} =  m_{2}  T_{2}

\frac{m_{2} }{m_{1}  } = \frac{T_{1} }{T_{2} }

\frac{m_{2} }{m_{1}  } = \frac{300}{354.54}

\frac{m_{2} }{m_{1}  } =0.00294

value of  the original mass of air in the tire should be released is  \frac{m_{2} - m_{1}}{m_{1}}

\frac{0.00294-1}{1}

⇒ -0.99706

% of the original mass of air in the tire should be released 99.706 %.

8 0
3 years ago
Please help..................​
worty [1.4K]

Answer:

PART A

In a solid

The attractive forces keep the particles together tightly enough so that the particles do not move past each other. ... In the solid the particles vibrate in place. Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.

In a liquid

Particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

A gas

The particles move rapidly in all directions, frequently colliding with each other and the side of the container. With an increase in temperature, the particles gain kinetic energy and move faster.

PART B

The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces. The more particles that hit the walls, the higher the pressure.

Explanation:

GOOD LUCK!!! :)

7 0
3 years ago
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