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Mazyrski [523]
3 years ago
8

5

Physics
1 answer:
Ronch [10]3 years ago
4 0

Answer:

Current in a parallel circuit = 0.61 amps (Approx)

Explanation:

Given:

Voltage V = 6 volt

Two resistors = 17.2 , 22.4 in parallel circuit

Find:

Current in a parallel circuit

Computation:

1/R = 1/r1 + 1 / r2

1/R = 1/17.2 + 1 / 22.4

R = 9.73 ohms (Approx)

Current in a parallel circuit = V / R

Current in a parallel circuit = 6 / 9.73

Current in a parallel circuit = 0.61 amps (Approx)

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How many times larger than a centigram is a dekagram
Umnica [9.8K]

Answer:

A dekagram is thousand (1000) times larger than a centigram.

Explanation:

→ [1 dekagram = 1,000 centigrams]

→ 1 dekagram = 10 grams

→ 10 grams = 100 decigrams

→ 100 decigrams = 1,000 centigrams

3 0
3 years ago
36 The height of a 30-story building is approximately
ohaa [14]
An approximation used to measure building height is 10 feet per building level.

Converting from feet to meters using the equation:
1 ft = 0.3048m
10 ft = 3.048m

Multiplying that by 30 storeys, we get:
3 x 3.048m = 91.44m, which is near the answer of (3) 10^2 m or 100m.
5 0
4 years ago
The picture to the right shows which wave behavior?
kifflom [539]

Answer:

It is refraction

Explanation:

6 0
3 years ago
Read 2 more answers
Find the elongation produced in a copper wire of length 2m and radius 5mm, when suspended by a block
igomit [66]

Answer:

0.104 m

Explanation:

Stress, \sigma=\frac {F}{A}

Where F is force and A is area. Also, F=mg where m is mass and g is acceleration due to gravity

Area= \pi r^{2}

Strain=\frac {\triangle l}{l} where \triangle l is the elongation and l is the original length

E=\frac {stress}{strain}=\frac {\frac {F}{A}}{\frac {\triangle l}{l}}=\frac {Fl}{A\triangle l}

Making \triangle l the subject then

\triangle l=\frac {Fl}{AE}=\frac{mg l}{\pi r^{2} E}

By substituting the given values and taking g as 9.81 then

\triangle l=\frac {Fl}{AE}=\frac{500\times 9.81\times 2 m}{\pi \times 0.005^{2}\times 1.2\times 10^{9}}=0.104087333  m\approx 0.104 m

3 0
3 years ago
A mover pushes a 30 kg crate across a level florr with a force of 250 N, but the crate accelerates at a rate of only 5.83 m/s sq
arlik [135]

Force of friction=75 N

Explanation:

we use Newton's second law of motion

F- Ff= ma

F = applied force=250 N

Ff= force of friction

a= acceleration= 5.83 m/s²

m= mass=30 kg

250- Ff= 30 (5.83)

Ff=250-30(5.83)

Ff=250-175

Ff=75 N

7 0
3 years ago
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