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Ivenika [448]
2 years ago
14

Can the triangles below be proven similar?

Mathematics
1 answer:
jeka942 years ago
3 0

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

<u>Yes </u><u>!</u><u> </u><u>they </u><u>ofcourse</u><u> </u><u>are </u><u>similar</u><u> </u><u>and </u><u>here </u><u>goes </u><u>the </u><u>explanation</u><u> </u><u>behind </u><u>that </u><u>~</u>

two triangles are said to be similar by SAS postulate in case the ratios of their side lengths comes out to be equal along with one angle lying in between the side lengths

<u>in </u><u>this </u><u>case </u><u>,</u>

\frac{AB}{BD}  \: should \: be \: equal \: to \:  \frac{EB}{BC} \\

so , let's check if the ratio is equal or no ~

\implies\frac{AB}{BD}  =  \frac{27}{18}  =  \frac{3}{2}  \\  \\ \implies \:  \frac{EB}{BC}  =  \frac{36}{24}  =  \frac{3}{2}  \\  \\ \therefore \:  \frac{AB}{BD}  =  \frac{EB}{BC}

Also ,

∠ABE = ∠CBD

<u>since </u><u>they </u><u>both </u><u>are </u><u>vertically</u><u> </u><u>opposite </u><u>,</u><u> </u><u>i.</u><u>e</u><u>.</u><u> </u><u>,</u><u> </u><u>angles </u><u>with </u><u>the </u><u>same </u><u>vertex </u><u>B </u><u>.</u>

thus the triangles are similar by SAS postulate !

hence , <u>Option </u><u>A</u> is correct !

hope helpful ~

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Vesna [10]
,52+(8+25)
=52+33
=88

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36

Step-by-step explanation:

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3 years ago
Mary Sue and Betty have 603 necklaces altogether. Mary Sue has 115 more necklaces than Betty. How many necklaces does Betty have
Blizzard [7]

Let Mary Sue have m necklaces and Betty have b necklaces.

And they have 603 necklaces altogether, that is

m + b =603

And Mary Sue has 115 more necklaces than Betty, that is

m=b +115

Substituting this value in first equation we will get

b+115+b=603

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So Betty have 244 necklaces .

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4 years ago
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Effectus [21]

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90mm cubed

Step-by-step explanation:

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3 years ago
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Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
3 years ago
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