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tino4ka555 [31]
3 years ago
11

Two women start at the same point. they walk in opposite directions for 3 meters, then turn right and walk another 4 meters. how

far apart are they?
Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

The total distance between the two women would simply be the sum of the hypotenuse formed by the triangular path they created.

For each women:

<span>c^2  = a^2 + b^2</span>

c^2 = 3^2 + 4^2

c^2 = 9 + 16

c^2 = 25

c = 5 m

Therefore the distance between the two is:

distance between the two women = 2 * c

<span>distance between the two women = 10 m</span>

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Answer:

Expand: x² + 11x + 11x + 121

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Step-by-step explanation:

To expand this, you can use the FOIL technique:

First terms

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Put these numbers together (expanded) to get:

x² + 11x + 11x + 121

Put the common terms together (simplify) to get:

x² + 22x + 121

Note:

Not sure if you need this info, but (x + 11)(x + 11) is the same as (x + 11)².

The numbers need to be in the order I put them in because you are supposed to place them in order greatest to least degree.

Hope it helps!

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3 years ago
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Aleksandr-060686 [28]

Answer:

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