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frozen [14]
3 years ago
15

To solve an equation, you use____operations.

Mathematics
1 answer:
Tema [17]3 years ago
5 0

Hey there!☺

Answer:\boxed{\text{inverse}}

Explanation:

When you are solving an equation, it is important to use <em>inverse</em> operations. You will need to use the <em>inverse</em> operations on both sides of the equation. And it is also important to isolate the variable. After you do that, you will need to reverse it up. The way to do all of this is using the <em>inverse</em>.

To solve an equation, you use <u>inverse</u> operations.

Hope this helps!

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A population has a mean of 300 and a standard deviation of 70. Suppose a sample of size 125 is selected and is used to estimate
Mrrafil [7]

Answer:

a:  0.8884

b: 0.9934

Step-by-step explanation:

We have µ = 300 and σ = 70.  The sample size, n = 125.  

For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:

P(292 < x < 308).

We need to find the z-scores that correspond to these values using the given data.  See attached photo 1 for the calculation of these scores.

We have P(292 < x < 308) = 0.8884

Next we want the probability of the sample mean to be within 17 units of the population mean, so we want the values from 283 to 317.  We want to find

P(283 < x < 317)

We need to find the z-scores that correspond to these values.  See photo 2 for the calculation of these scores.

We have P(283 < x < 317) = 0.9934

5 0
3 years ago
Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco
Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

d=136

The first part of the trip there was lots of traffic, she only averaged 16 mph;

v_1=16

The second part of the trip there was no traffic so she could drive 44 mph;

v_2=44

She traveled for a total of 5 hours;

t=5

let x represent the time in traffic when she traveled at 16 mph

t_1=x

the time the traffic is clear would be;

t_2=t-t_1=5-x

Recall that distance equals speed multiply by time;

d=v_1t_1_{}_{}^{}+v_2t_2

substituting the values;

136=16x+44(5-x)

solving for x;

\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}

So;

\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0
1 year ago
(4y^2)^3(3y^2) Please help :)
Ierofanga [76]

Answer:

192y^8

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is 2 5/6 +1 5/7
mylen [45]
Hi Cherise1cherhop lets break this equation down with these steps:

1) add the whole numbers first

2) find the LCD of the fractions and that would be 42 since 42 can go into both denominators through multiplication

3) make the denominators (bottom numbers) the same as the LCD (42)

4) simplify it, now the denominators are equal

5) join the denominators together

6) simplify it (3 + 65/42)

7) convert 65/42 to mixed fraction

8) now that we made it a mixed fraction, simplify it

Answer: 4 23/42
8 0
3 years ago
Please solve this question fast.
Alexxandr [17]

Answer:

See Explanation

Step-by-step explanation:

{a} =  {6}^{x},  \:  \: b = {6}^{y}  ...(given) \\  {a}^{y}. {b}^{x}  = 36..(1) \\ pluggig \: the \: values \: of \: a \: and \: b \: in \: (1) \\  ({6}^{x}) ^{y} . ({6}^{y}) ^{x} =  {6}^{2}  \\ {6}^{xy}.{6}^{xy} =  {6}^{2}  \\  {6}^{xy + xy}  =  {6}^{2}  \\  {6}^{2xy}  =  {6}^{2}  \\ bases \: are \: equal \: so \: exponentes \: will \: also \: be\\ \: equal \\  \therefore \: 2xy = 2 \\ xy =  \frac{2}{2}  \\ \huge \red { \boxed{ xy = 1}} \\ hence \: proved \\

3 0
3 years ago
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