Test the value (x,y) of each point in the equation-y^2 + x <= -4 BY
1) because the equation has = so every point in the equation -y^2 + x = -4 is applied .... this case is B ... satisfy 2) A, E is in the same area choose one to test test A(-4,2) : -(2)^2 + (-4) <= -4 which is true the A and E is satisfy the inequality 3) no need to test fo C, D, F on the different area they are not satisfy. but you can guess it will satisfy -y^2 + x > -4
Answer:
x=-1,y=0
Step-by-step explanation:
-10y+9x=-9
10y+5x=-5
14x=-14
x=-1
-10y-9=-9
y=0
x = - 1
given
= x + 3
square both sides
1 - 3x = (x + 3 )² ( expand right side using FOIL )
1 - 3x = x² + 6x + 9 ( subtract 1 - 3x from both sides )
0 = x² + 9x + 8
0 = ( x + 1)(x + 8)
equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = -1
x + 8 = 0 ⇒ x = - 8
As a check
substitute these values into the equation and if both sides are equal then they are the solutions
x = - 1 :
= 2 and - 1 + 3 = 2 ← true
x = - 8 :
= 5 and - 8 + 3 = -5 ← false
thus the only solution is x = - 1
Step-by-step explanation: 3
Draw 37 circles and then use / slashes and cross out 19 of those circles