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alexdok [17]
1 year ago
15

Un círculo con circunferencia igual a 20 tiene un arco con ángulo central igual a 72°.

Mathematics
1 answer:
Citrus2011 [14]1 year ago
6 0

Answer:

4

Step-by-step explanation:

\frac{20}{360}=\frac{x}{72}\\x = 4

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HELP ASAP PLZ PLZ PLZ I GIVE BRAINLIEST
Yuki888 [10]

Answer:

12

Step-by-step explanation:

We can see that the base TA is 4, and the second base RS is 2. We can see that the height is 4. The area of a trapezoid is:

A=\frac{h(b_1+b_2)}{2}

Using this, we can substitute, and get:

A=\frac{4\cdot(2+4)}{2} = \frac{24}{2} = 12

Hope it helps!!

5 0
3 years ago
the thickness of a cd is about 1/20 inch. if carrie has a stack of 52 cds,what is the height of the stack
tatyana61 [14]
The answer would be 26 because you're multiplying .5 times 52
8 0
3 years ago
1. What is the slope of a line that is parallel to the line represented by the equation y=-2/5x + 4/5
lbvjy [14]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .  . . . . . . . . .

We are asked to find the slope of the line that is parallel to the line \star~\mathrm{y=-\cfrac{2}{5}x+\cfrac{4}{5}}.

\triangle~\fbox{\bf{KEY:}}

  • Parallel lines have the same slope.

So let's first determine the slope of the first line, and then let's find the slope of the line that's parallel to it.

\circ\!\!\!\star\mathcal{HINT:}

  • The slope is the coefficient of x.

So the slope is

\star~\mathrm{-\cfrac{2}{5}}.

Can you guess the slope of the line that is parallel to the first line?

That's right! The slope is...

\star~\mathrm{-\cfrac{2}{5}}

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

4 0
2 years ago
Solve: <br><br> -2 1/3-(-5)= what<br><br><br> Please help
OLEGan [10]

Answer:

8/3

Step-by-step explanation:

\frac{ - 7}{3}  + 5 =  \frac{8}{3}

7 0
3 years ago
Wat property is this x-10=15
leva [86]
X is 25 beceause 25-10=15



3 0
3 years ago
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