4,000 in bank -500 and 15000 so she had -20000 +4000 so it equals -16000
The Number is 79500, since the nearest thousand for 79500 is 80000
sorry I don't solve this problem
Answer:
n+2
Step-by-step explanation:
This is a Typical Question on Arithmetic Progression with initial term as 2n+1
The next number in this particular series will be 2n+1+2 which is 2n+3 and so on. Thus a common difference of 2 exists.
The nth term of an Arithmetic Progression AP, bn is represented below where b1 is the first term
bn=b1 +(n-1)d where d is the common difference
For this particular series, the 4th term b4 is
b4= 2n+1+(4-1)2 0r b4 =2n+1+6=2n+7
sum of series is represented by equation: n(b1 +b4)/2 where b1 and b4 are 1st and 4th term respectively
Thus Sum required =4(2n+1+2n+7)/2=4(4n+8)/2=8n+16 0r n+2
Answer:
The number of permutations of the group of letters given (J, K, L, M, N, O and P) is 7! = 7 . 6 . 5 . 4 . 3 . 2 . 1 = 5,040.
Step-by-step explanation:
The number of permutations without repetition is the number of possible sequences that can occur if we take the letters one by one and is calculated with the factorial of the total number of letters in the group.
Before starting we have 7 possibilities, one for each letter. Once the first letter is chosen randomly, we will have 6 possibilities, after taking the third letter we will have 5 possibilities, and so on.
In total the total number of possibilities to obtain the 7 letters in a certain order are 7 by 6 by 5 by 4 by 3 by 2 by 1, sayed in other words factorial of 7 (7!). The result of the multiplication gives 5,040.
In short we can get the seven letters in 5,040 different sequences.
