Pythagorean Theorem can be used only for right triangles.
(leg1)² +(leg2)² = hypotenuse ²
So, answer is the right triangle B.
This requires the Poisson distribution, where
area = 5-acres
and mean number of field mice = 12 (in 5-acres of field)
therefore
lambda=12 (mean, given)
and the probability of k mice in the 5-acre field is given by the Poisson distribution as
P(X=k)=lambda^k * e^(-lambda) / k! ..............(1)
To find the probability of having LESS than 7 field mice, we add the probabilities of 0 to 6, which is
P(X<7)=P(X=0)+P(X=1)+...+P(X=6)
evaluating with equation (1) for X=0 to 6, we get:
0 0.0000061 0.0000742 0.0004423 0.0017704 0.0053095 0.0127416 0.025481Total = 0.045822
Answer: The probability that fewer than 7 field mice are found in the 5-acre field is 0.0458.
A = 75
B = not sure
C = 156
So the answer is A. Hope it helps :)
Answer:
x = 14
Step-by-step explanation:
In the triangle O is the centroid.
Now, we know that the centroid divides the medians in the 2 : 1 ratio that means the distance from the centroid to the vertex and the distance from the centroid to the opposite side remains in 2 : 1 ratio.
So, from the given diagram we can write
⇒ 3x = 4x - 14
⇒ x = 14 (Answer)
