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kari74 [83]
2 years ago
9

Please help me with this I would give you 50 points. FEET 1 4 5 INCHES 24 36

Mathematics
2 answers:
kipiarov [429]2 years ago
6 0

Answer: feet: 1, 2, 3, 4, 5

          inches: 12, 24, 36, 48, 60

Step-by-step explanation:

There are 12 inches in a foot, therefore if you have 1 foot you have 12 inches, if you have 2 feet you have 24 inches becauase 2*12 = 24 and so on...

FinnZ [79.3K]2 years ago
4 0
There are 12 inches in 1 foot. Therefore, 1 ft = 12 inches, 2ft=24 inches 3ft =36inches, and so on.
To find how many inches = the amount of feet you would simply multiply the number of feet by 12.
For example 4ft would be 4x12=48. Or 5ft would be 5x12=60
Therefore 4ft =48inches. And 5ft =60inches
If u are given an amount in inches to determine feet you would divide by 12
For example
84 inches into feet would be solved by dividing 84by 12
84/12=7
you now know that 84inches =7feet
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Answer:

<h2>C. g(x) = x - 6</h2>

Step-by-step explanation:

For a parent function y = f(x) and n > 0:

f(x) + n : move the graph n units up

f(x) - n : move the graph n units down

f(x + n) : move the graph n units to the left

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The ratio of the number of cookies to the number of candies in different gift boxes is 5:7. Which table best shows the number of
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Answer:

-------------------------------------------------------------------

Ratio

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cookies : candies

     5     :     7

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Using the normal distribution, it is found that she scores less than 128 in 28.1% of her games.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

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In this problem, the mean and the standard deviation are given, respectively, by \mu = 135, \sigma = 12.

The proportion of games in which she scores less than 128 is the <u>p-value of Z when X = 128</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{128 - 135}{12}

Z = -0.58

Z = -0.58 has a p-value of 0.281.

She scores less than 128 in 28.1% of her games.

More can be learned about the normal distribution at brainly.com/question/24663213

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