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ludmilkaskok [199]
2 years ago
8

Prove: An odd number squared is an odd number. = (2n + 1)2 ​

Mathematics
1 answer:
Mnenie [13.5K]2 years ago
4 0

Answer:

{(2n + 1)}^{2}  = 4 {n}^{2}  + 4n + 1 = 2(2 {n}^{2}  + 2n) + 1

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Can y’all help me on this one<br><br> What’s the answer?
Rudik [331]

Answer:

x = 2

Step-by-step explanation:

First translate the image into an equation using the key. Once you do that, your equation should look like this:

(x + x + x) + (-1 + -1 + -1 + -1 + -1) = (-x + -x) + (1 + 1 + 1 + 1 + 1)

________________________________

3x - 5 = -2x + 5

(given)

________________________________

3x - 5 = -2x + 5

+5. +5

(addition property of equality)

*cancel out -5 on the left hand side, and isolate it from x by adding +5 on each side*

__________________________

3x = -2x + 10

+2x +2x

(addition property of equality)

*cancel out the negative 2x, and isolate it from the constant term on the right hand side by adding 2x on both sides*

________________________________

5x = 10

÷5. ÷5

(division property of equality)

*divide by 5(GCF) on both sides to isolate

x by itself*

________________________________

<u>x = 2</u>

________________________________

If you want to test this solution, substitute this back into the equation.

x = 2 → 3x - 5 = -2x + 5. 3(2) - 5 = -2(2) + 5 = 6 - 5 = -4 + 5 = <u>1 = 1</u>

7 0
3 years ago
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