Answer:
x = -3
, y = 0
Step-by-step explanation:
Solve the following system:
{4 x - y = -12 | (equation 1)
-x - y = 3 | (equation 2)
Add 1/4 × (equation 1) to equation 2:
{4 x - y = -12 | (equation 1)
0 x - (5 y)/4 = 0 | (equation 2)
Multiply equation 2 by 4/5:
{4 x - y = -12 | (equation 1)
0 x - y = 0 | (equation 2)
Multiply equation 2 by -1:
{4 x - y = -12 | (equation 1)
0 x+y = 0 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = -12 | (equation 1)
0 x+y = 0 | (equation 2)
Divide equation 1 by 4:
{x+0 y = -3 | (equation 1)
0 x+y = 0 | (equation 2)
Collect results:
Answer: {x = -3
, y = 0
15. -2
16. A. The pool was originally empty
Answer:
Number 1
Step-by-step explanation:
The median in number 1 is 13 and the range for number 1 is also thirteen so it has to be it.
4(5x-20)=-20
20x-80=-20
20x=60
x=3
Ok so what you're trying to do is get L by itself so to do this you move everything to the other side:
A=L*WH

=L
So you answer would be:
C