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2 years ago

Please help me, I’m only five more questions away from being done

Mathematics

1 answer:

djyliett [7]2 years ago

5 0

Answer:

${2t}^{3} + {20t}^{2} - 2t + 15$

Hope this helps!!

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Can someone solve 3y − 3 = 2y + 6 step by step Like the example below

adell [148]

3y - 3 = 2y + 6

-2y -2y

y - 3 = 6

-3 -3

y = 3

4 0

3 years ago

Read 2 more answers

A bag contains 4 red and 6 green gumballs. if you select 5 of them without looking, how many ways can you get exactly 3 red or e

marusya05 [52]

This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,

4C3 = 4!/3!(4 - 3)! = 4 ways

If you want to get 2 green out of the total 6, then that would be 6C2. That means,

6C2 = 6!/2!(6-2)! = 15 ways

Therefore, there are a total of 4+15 = 19 ways.

8 0

4 years ago

Question 2 (Essay Worth 10 points)

icang [17]

Answer:

Part A: 1 solution

Part B:

3(2x-7)=3

6x-21=3

+21 +21

6x=24

/6 /6

x=4

Step-by-step explanation:

First you distribute 3(2x-7)=3 to 6x-21=3. Next you do inverse operations by adding 21 to both sides of the equation to get 6x=24. Finally you divide both sides by 6 to get x=4

7 0

3 years ago

Solve. Show all your work and explain your steps.

vitfil [10]

The problem does not clearly give us the distance from Buffalo to Chicago, so let this be x (in mile) just so I can show you how the total cost is solved.
The total cost is equal to the sum of the rental fee plus the cost of the additional fee per mile which is equal to 1.50x, and also of the cost of the gasoline which is equal to (x/16)(2.15). Thus, the final answer should be expressed as,
total cost = 29.95 + 1.5x + 2.15x/16
When the distance is available, this should be easily substituted in the equation above.

7 0

3 years ago

-6n5x^3÷18nx^7 12m^8y^6÷-9my^4

umka2103 [35]

Answer:

(-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

Step-by-step explanation:

Simplify the following:

(-6 n^5 x^3)/(18 n x^7) + (12 m^8 y^6)/(-9 m y^4)

The gcd of -6 and 18 is 6, so (-6 n^5 x^3)/(18 n x^7) = ((6 (-1)) n^5 x^3)/((6×3) n x^7) = 6/6×(-n^5 x^3)/(3 n x^7) = (-n^5 x^3)/(3 n x^7):

(-1 n^5 x^3)/(3 n x^7) + (12 m^8 y^6)/(-9 m y^4)

Combine powers. (-n^5 x^3)/(3 n x^7) = (n^(5 - 1) x^(3 - 7) (-1))/3:

-(n^(5 - 1) x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

5 - 1 = 4:

-(n^4 x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

3 - 7 = -4:

-(n^4 x^(-4))/3 + (12 m^8 y^6)/(-9 m y^4)

The gcd of 12 and -9 is 3, so (12 m^8 y^6)/(-9 m y^4) = ((3×4) m^8 y^6)/((3 (-3)) m y^4) = 3/3×(4 m^8 y^6)/(-3 m y^4) = (4 m^8 y^6)/(-3 m y^4):

(4 m^8 y^6)/(-3 m y^4) - (n^4)/(3 x^4)

Combine powers. (4 m^8 y^6)/(-3 m y^4) = (4 m^(8 - 1) y^(6 - 4))/(3 (-1)):

-(n^4)/(3 x^4) + (4 m^(8 - 1) y^(6 - 4))/(-3)

8 - 1 = 7:

-(n^4)/(3 x^4) + (4 m^7 y^(6 - 4))/(-3)

6 - 4 = 2:

-(n^4)/(3 x^4) + (4 m^7 y^2)/(-3)

Multiply numerator and denominator of (4 m^7 y^2)/(-3) by -1:

-4/3 m^7 y^2 - (n^4)/(3 x^4)

Put each term in -(n^4)/(x^4×3) - (4 m^7 y^2)/3 over the common denominator 3 x^4: -(n^4)/(x^4×3) - (4 m^7 y^2)/3 = (-n^4)/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4):

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4)

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4) = (-n^4 - 4 m^7 x^4 y^2)/(3 x^4):

Answer: (-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

5 0

3 years ago