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Artist 52 [7]
4 years ago
13

Choose the function that shows the correct transformation of the quadratic function shifted eight units to the left and one unit

down.
ƒ(x) = (x - 8)2 - 1
ƒ(x) = (x - 8)2 + 1
ƒ(x) = (x + 8)2 - 1
ƒ(x) = (x + 8)2 + 1
Mathematics
2 answers:
Wittaler [7]4 years ago
8 0
The vector[-8;-1]

f(x)=(x+8)^2-1


:)
MrRa [10]4 years ago
7 0

Answer:

The correct option is 3.

Step-by-step explanation:

The parent quadratic function shifted is

f(x)=x^2

The translation is defined as

f(x)=(x+a)^2+b                .... (1)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

It is given that the quadratic function shifted 8 units left and 1 units down. It means a=8 and b=-1.

Substitute a=8 and b=-1 in equation (1).

f(x)=(x+8)^2+(-1)

f(x)=(x+8)^2-1

Therefore the correct option is 3.

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warwar

Step-by-step explanation:

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3 years ago
Function question<br><br>read the graph then solve
viktelen [127]

Answer:

  1. g(5x) = 0
  2. x = -10

Step-by-step explanation:

Do what your instructions say: read the graph and solve.

1. In order to find x, you look for the point where g(x) is 4. That point is found where x = -2. (See the first attachment.)

Then 5x = 5·(-2) = -10. To answer the question, you need to find the value of g(-10). Look where the graph crosses the vertical line at x=-10. It is at y=0, so ...

... g(5x) = g(-10) = 0

2. You already found the answer to this when looking for the answer to the first question. g(x) = 0 when x = -10. (See the second attachment.)

7 0
3 years ago
Find the area of the shape
Oliga [24]

Answer:

27 pi

Step-by-step explanation:

First find the area of a circle

A = pi r^2

A = pi ^^2

36 pi

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6 0
4 years ago
How do you write 280% as a fraction or mixed numbers?
Taya2010 [7]

Step-by-step explanation:

Fraction = 280% / 100%

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7 0
3 years ago
Read 2 more answers
Find the area of a trapezium whose parallel sides are 28.7 cm and 22.3 cm and distance between parallel sides is 16 cm.
puteri [66]

Given:

The parallel sides of a trapezium are 28.7 cm and 22.3 cm.

The distance between parallel sides is 16 cm.

To find:

The area of a trapezium.

Solution:

The area of the trapezium is:

A=\dfrac{a+b}{2}h

Where, a,b are parallel sides and h is the vertical distance between the parallel sides.

Putting a=28.7, b=22.3,h=16 in the above formula, we get

A=\dfrac{28.7+22.3}{2}\times(16)

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A=51\times 8

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Therefore, the area of the trapezium is 408 square cm.

4 0
3 years ago
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