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Artist 52 [7]
4 years ago
13

Choose the function that shows the correct transformation of the quadratic function shifted eight units to the left and one unit

down.
ƒ(x) = (x - 8)2 - 1
ƒ(x) = (x - 8)2 + 1
ƒ(x) = (x + 8)2 - 1
ƒ(x) = (x + 8)2 + 1
Mathematics
2 answers:
Wittaler [7]4 years ago
8 0
The vector[-8;-1]

f(x)=(x+8)^2-1


:)
MrRa [10]4 years ago
7 0

Answer:

The correct option is 3.

Step-by-step explanation:

The parent quadratic function shifted is

f(x)=x^2

The translation is defined as

f(x)=(x+a)^2+b                .... (1)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

It is given that the quadratic function shifted 8 units left and 1 units down. It means a=8 and b=-1.

Substitute a=8 and b=-1 in equation (1).

f(x)=(x+8)^2+(-1)

f(x)=(x+8)^2-1

Therefore the correct option is 3.

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Harlamova29_29 [7]

Answer:

1026.02, you can round that online

Step-by-step explanation:

6 0
3 years ago
Can any one please help me to do e and d please can anyone do it for me please
Semenov [28]

Answer:

d = 520 cm^3   e = 1717.66 cm^2

Step-by-step explanation:

d) The area of the face triangle is 40 and multiply that with the length, 13 to get 520.

e) The volume of the half circle is 190.85 and the volume of the cone is 1526.81 and add them

6 0
4 years ago
Evaluate 11c3 and 11p4
In-s [12.5K]

_{n}C_{r} = \frac{n!}{r!(n-r)!}  \\ \\ _{11}C_{3}= \frac{11!}{3!*(11-3)!} =\frac{11*10*9*8*7*6*5*4*3*2*1}{3*2*1*8*7*6*5*4*3*2*1} =\frac{11*10*9}{3*2} =165 \\ \\_{11}C_{4}=\frac{11!}{4!(11-4)!} =\frac{11*10*9*8*7!}{4!*7!} =\frac{11*10*9*8}{4*3*2*1} =330

7 0
3 years ago
Read 2 more answers
Jonathan went to the movies with $48 he earned at his after-school job. The ticket cost $8.75. He spent $7.45 for refreshments.
aleksley [76]

Answer:

8.75+7.45=16.2. 16.2 is equal to $16.20 so 48.00-16.20=31.8. Jonathan had $31.80 left.

Step-by-step explanation:

7 0
3 years ago
A hexagonal prism 6 ft tall with a regular base measuring 9 ft on each edge and an apothem of length 7.8 ft. How do I get the la
SIZIF [17.4K]
Given:

Hexagonal Prism dimensions: 

Altitude = 6 ft
Regular base;
side = 9 ft
apothem = 7.8 ft

The formula for the lateral surface area of a prism is

LA = P * h

where 
LA is the lateral surface area
P is the perimeter of the base
h is the height of the prism

LA = (9 ft * 6 sides) * 6 ft
LA = 324 ft^2

The formula for total surface area is 

TA = (P * h) + 2(Ab) 

where 
TA is the total surface area
Ab = Area of the base

Ab = a * P / 2
Ab = 7.8 ft * (9ft * 6) / 2
Ab = 210.6 ft^2

TA = 324 + 2(210.6)
TA = 745.2 ft^2
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8 0
3 years ago
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