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1 year ago

Which step is the same when constructing an inscribed square and an inscribed regular hexagon?

Mathematics

1 answer:

AfilCa [17]1 year ago

7 0

Answer:

Step-by-step explanation:

Connect every arc along the circle.

Construct a circle of any arbitrary radius.

Set the compass width to greater than half the diameter of the circle.

Set the compass width to the radius of the circle.

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Evaluate and Explain 3t(t+2)-3t^2 for t=19 and Simplifiy -(3a-2b)-3(-a-b)

Yuri [45]

1 ) 3 t ( t + 2 ) - 3 t² =
= 3 t² + 6 t - 3 t² = 6 t = 6 · 19 = 114

2 ) - ( 3 a - 2 b ) - 3 ( - a- b ) =
= - 3 a + 2 b + 3 a + 3 b = 5 b

5 0

2 years ago

Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10

damaskus [11]

Answer:

Step-by-step explanation:

set

$f(x,y)=x+y\\$

constrain:

$g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10$

Partial derivatives:

$f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2$

Lagrange multiplier:

$grad(f)=a*grad(g)+b*grad(h)\\$

$\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]$

4 equations:

$1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10$

By solving:

$a=4/9\\b=-2/27\\x+y=4$

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

$x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4$

The maximum is 4

6 0

3 years ago

A flagpole broke in a storm. It was originally 81 8181 feet tall. 28 2828 feet are still sticking straight out of the ground, wh

solong [7]

Answer:

The end of the flagpole is 50.79 ft away from the base of the pole.

Step-by-step explanation:

The problem is represented by the diagram below.

The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).

The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).

Using Pythagoras theorem, we have that:

$hyp^2 = adj^2 + opp^2$

=> $53^2 = x^2 + 28^2$

$3364 = x^2 + 784\\\\=> x^2 = 3364 - 784\\\\x^2 = 2580\\\\x = \sqrt{2580}\\ \\x = 50.79 ft$

The end of the flagpole is 50.79 ft away from the base of the pole.

7 0

3 years ago

The Esteban family will order one T-shirt for each person who attends their family reunion. The cost is $6.50 per T-shirt plus a

Ilia_Sergeevich [38]

You plug in 2000 for c
Then u subtract 35 from 2,000 and get 1,965
Then u divide 1,965 by 6.5 and u get 302.3 but your actual answer is 302 T-shirts

Answer: 302 T-shirts

6 0

3 years ago

What fractions are greater than 7/12

Vsevolod [243]

Answer:

8/12 and higher. To ensure an accurate answer, are there other fractions to compare "7/12" to?

Step-by-step explanation:

8 0

2 years ago