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2 years ago

What is the simplest form of 2 square root of 2 over square root of 3 minus square root of 2

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

7 0

The answer would be A or 2 square root of 6 + 4!! Hope that helped please give me 5 stars and a thanks! Thanks so much ! Do well on your test!

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7x + 3(5 - 3x) =5 <br> x=?

harina [27]

Answer:

x=5

Step-by-step explanation:

7x+15-9x=5

-2x+15=5

-2x=-10

x=5

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2 years ago

-8(x+4)=40<br> Please show step by step

erastova [34]

Answer:

x=-1

Step-by-step explanation:

-8x+32=40

-8x=8

x=-1

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2 years ago

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11Alexandr11 [23.1K]

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2 years ago

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tia_tia [17]

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Step-by-step explanation:

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2 years ago

Select all possible values for x in the equation x^3=375?

Helga [31]

<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

To solve the problem, we need to remember the following properties of the exponents and roots:

$a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}$

Then, we are given the expression:

$x^{3}=375$

So, finding "x", we have:

$x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}$

Hence, the possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

Have a nice day!

7 0

3 years ago