Answer:
(-4,2) belongs in this direct variation.
Step-by-step explanation:
Let the direct variation relationship is expressed by the equation y = mx ........ (1), where x and y are in direct variation and k is the variation constant.
Now, the point (4,-2) is included in the direct variation relationship, then from equation (1) we get, -2 = 4m
⇒
Therefore, the equation (1) becomes
⇒ x + 2y = 0 ......... (2)
Now, from the given four options only the point (-4,2) satisfies the relation (2).
Hence, (-4,2) belongs in this direct variation. (Answer)
