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snow_lady [41]
1 year ago
11

Question 2 of 25

Computers and Technology
1 answer:
levacccp [35]1 year ago
4 0
A, as a lower resolution will store less data per frame, reducing file size.
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Properly worn safety belts help prevent
marissa [1.9K]

Answer:

True

Explanation:

This one was a bit tricky because I've never heard that as a feature, but it is true that they could be of help.

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Business intelligence software can help managers ________.
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Business intelligence can be used by managers in order to see how well their departments are. Now go and get that A+
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Would this program compile run? If not, why; if yes: what would be the output? public class ConstChaini { public static void mai
nikdorinn [45]

Answer:

Check the explanation

Explanation:

// Code to copy

public class ConstChain1 {

public static void main(String[] args)

{

new SubClass();

System.out.println();

new SubClass(1);

}

}

class SuperClass{

public SuperClass() {

System.out.println("D");

}

public SuperClass(int i) {

System.out.println("C");

}

}

class SubClass extends SuperClass{

public SubClass() {

this(10);

System.out.println("B");

}

public SubClass(int i) {

super(i);

System.out.println("A");

}

}

Explanation:

Now each time when a object of a subclass is been created it's super class constructor will be executed first then only subclass object is created by executing it's constructor.

8 0
2 years ago
What is .net formatting?
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Basically replacing a certain formatting for a certain product 
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3 years ago
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Create a function void process(char ch, int x, int y)- to accept an arithmetic operator (+,-./, in argum
saul85 [17]

Answer:

The program is as follows:

import java.util.*;

public class Main{

   public static void process(char ch, int x, int y){

if(ch == '+'){

    System.out.print(x+y);  }

else if(ch == '-'){

    System.out.print(x-y);  }

else if(ch == '*'){

    System.out.print(x*y);  }

else if(ch == '/'){

    if(y!=0){

        double num = x;

        System.out.print(num/y);      }

    else{

        System.out.print("Cannot divide by 0");     } }

else{

    System.out.print("Invalid operator"); }

 }

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int x, y;

 char ch;

 System.out.print("Enter two integers: ");

 x = input.nextInt(); y = input.nextInt();

 System.out.print("Enter operator: ");

 ch = input.next().charAt(0);  

 process(ch,x, y);

}

}

Explanation:

The function begins here

   public static void process(char ch, int x, int y){

If the character is +, this prints the sum of both integers

<em> if(ch == '+'){</em>

<em>     System.out.print(x+y);  }</em>

If the character is -, this prints the difference of both integers

<em> else if(ch == '-'){</em>

<em>     System.out.print(x-y);  }</em>

If the character is *, this prints the product of both integers

<em> else if(ch == '*'){</em>

<em>     System.out.print(x*y);  }</em>

If the character is /, this prints the division of both integers.

<em> else if(ch == '/'){</em>

<em>     if(y!=0){</em>

<em>         double num = x;</em>

<em>         System.out.print(num/y);      }</em>

<em>     else{</em>

<em>This is executed if the denominator is 0</em>

<em>         System.out.print("Cannot divide by 0");     } }</em>

Invalid operator is printed for every other character

<em>else{</em>

<em>     System.out.print("Invalid operator"); }</em>

<em> </em> }

The main begins here

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

This declares both integers

 int x, y;

This declares the operator

 char ch;

Get input for both integers

<em>  System.out.print("Enter two integers: ");</em>

<em>  x = input.nextInt(); y = input.nextInt();</em>

Get input for the operator

<em>  System.out.print("Enter operator: ");</em>

<em>  ch = input.next().charAt(0);   </em>

Call the function

 process(ch,x, y);

}

}

6 0
3 years ago
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