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1 year ago

Question 2 of 25

Computers and Technology

1 answer:

levacccp [35]1 year ago

4 0

A, as a lower resolution will store less data per frame, reducing file size.

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Properly worn safety belts help prevent

marissa [1.9K]

Answer:

True

Explanation:

This one was a bit tricky because I've never heard that as a feature, but it is true that they could be of help.

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Business intelligence software can help managers ________.

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3 years ago

Would this program compile run? If not, why; if yes: what would be the output? public class ConstChaini { public static void mai

nikdorinn [45]

Answer:

Check the explanation

Explanation:

// Code to copy

public class ConstChain1 {

public static void main(String[] args)

{

new SubClass();

System.out.println();

new SubClass(1);

}

class SuperClass{

public SuperClass() {

System.out.println("D");

}

public SuperClass(int i) {

System.out.println("C");

}

class SubClass extends SuperClass{

public SubClass() {

this(10);

System.out.println("B");

}

public SubClass(int i) {

super(i);

System.out.println("A");

}

Explanation:

Now each time when a object of a subclass is been created it's super class constructor will be executed first then only subclass object is created by executing it's constructor.

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2 years ago

What is .net formatting?

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3 years ago

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Create a function void process(char ch, int x, int y)- to accept an arithmetic operator (+,-./, in argum

saul85 [17]

Answer:

The program is as follows:

import java.util.*;

public class Main{

public static void process(char ch, int x, int y){

if(ch == '+'){

System.out.print(x+y); }

else if(ch == '-'){

System.out.print(x-y); }

else if(ch == '*'){

System.out.print(x*y); }

else if(ch == '/'){

if(y!=0){

double num = x;

System.out.print(num/y); }

else{

System.out.print("Cannot divide by 0"); } }

else{

System.out.print("Invalid operator"); }

}

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

int x, y;

char ch;

System.out.print("Enter two integers: ");

x = input.nextInt(); y = input.nextInt();

System.out.print("Enter operator: ");

ch = input.next().charAt(0);

process(ch,x, y);

}

Explanation:

The function begins here

public static void process(char ch, int x, int y){

If the character is +, this prints the sum of both integers

if(ch == '+'){

System.out.print(x+y); }

If the character is -, this prints the difference of both integers

else if(ch == '-'){

System.out.print(x-y); }

If the character is *, this prints the product of both integers

else if(ch == '*'){

System.out.print(x*y); }

If the character is /, this prints the division of both integers.

else if(ch == '/'){

if(y!=0){

double num = x;

System.out.print(num/y); }

else{

This is executed if the denominator is 0

System.out.print("Cannot divide by 0"); } }

Invalid operator is printed for every other character

else{

System.out.print("Invalid operator"); }

}

The main begins here

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

This declares both integers

int x, y;

This declares the operator

char ch;

Get input for both integers

System.out.print("Enter two integers: ");

x = input.nextInt(); y = input.nextInt();

Get input for the operator

System.out.print("Enter operator: ");

ch = input.next().charAt(0);

Call the function

process(ch,x, y);

}

6 0

3 years ago