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ad-work [718]
2 years ago
14

(cos 2theta)/(1 + sin 2theta) = (1 - tan theta)/(1 + tan theta)

Mathematics
1 answer:
andre [41]2 years ago
3 0

Step-by-step explanation:

Here is the solution...hope it helps:)

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Please help I need to finish my homework
valina [46]

Answer:

AB= 0.625 units (3 s.f.)

∠BAC= 52.9° (1 d.p.)

∠ABC= 32.1° (1 d.p.)

Step-by-step explanation:

Please see the attached pictures for full solution.

- Find AB using cosine rule

- find ∠BAC using sine rule

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4 0
3 years ago
Help for e???????????????????
Aliun [14]
3 is the answer they are after 40
7 0
3 years ago
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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
If AB=BC, AB=4x-2, and BC= 3x+3, find AB
a_sh-v [17]
Isnt it 4x-2 ?? i mean it does say "find" AB...
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3 years ago
A number t<br> multiplied by −4<br> is at least −25<br> .
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3 years ago
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