Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer: y = 0.5, x = 50
Step-by-step explanation: Both triangles in the picture are isosceles, telling us that the 2 angles at the bottom are congruent. With this, we can find y by doing the following:
a triangle has 180 degrees so we subtract the given 50 which gives us 130
2(2y + 64) = 130
4y + 128 = 130
y = .5
This means that the bottom 2 angles are both 65. Since the top angle of the second triangle is supplementary to the bottom angle of the first one, the top angle of the second triangle is 115. So, we find x by:
2(45 - x/4) = 65
x = 50
This means the bottom 2 angles of the second triangle are both 32.5.
Answer:
2x+5 r. 13
Step-by-step explanation:
So using long division, you can solve for the quotient and the remainder.
Please look at the attached for the solution.
Step 1: need to make sure that you right the terms in descending order. (If there are missing terms in between, you need to fill them out with a zero so you won't have a problem with spacing)
Step 2: Divide the highest term in the dividend, by the highest term in the divisor.
Step 3: Multiply your result with the divisor and and write it below the dividend, aligning it with its matched term.
Step 4: Subtract and bring down the next term.
Repeat the steps until you cannot divide any further. If you have left-overs that is your remained.
