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Verdich [7]
2 years ago
5

Can someone please help me with this

Mathematics
1 answer:
oee [108]2 years ago
6 0

Answer:

165 pennies

Step-by-step explanation:

250/1.52=164.473684211, but just round it to the nearest whole number whitch would be 165!

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What is the solution to this equation x -9=5​
lukranit [14]

Answer:

x = 14

Step-by-step explanation:

x- 9 = 5

Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x. Add 9 to both sides of the equation:

x - 9 (+9) = 5 (+9)

x = 5 + 9

x = 14

x = 14 is your answer.

~

7 0
3 years ago
An equation is... ____________.
Inessa [10]

Answer:

a mathematical sentence thar has an equal sign

5 0
2 years ago
Plot the image of point D under a dilation about point P with a scale factor of
Vikentia [17]
It’s at point d and point p
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3 years ago
What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
In the diagram, triangle GEF and triangle HEF are congruent. What is the value of x?
Harrizon [31]
2(x+2) = 60
x+2 = 30
x = 28
The correct answer is C
8 0
3 years ago
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