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AfilCa [17]
2 years ago
7

Rewrite! Write an new and equivalent equation that is easier to solve

Mathematics
2 answers:
RUDIKE [14]2 years ago
8 0

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>an </u><u>equation </u><u>in </u><u>it's</u><u> </u><u>general </u><u>form</u>

  • To do - <u>convert </u><u>the </u><u>given</u><u> </u><u>equation</u><u> </u><u>into </u><u>a </u><u>form </u><u>that </u><u>is </u><u>easy </u><u>to </u><u>solve</u>

<u>Given </u><u>equation</u><u> </u><u>-</u>

\bold{(x + 2) {}^{2}  + 4(x + 2) - 5 = 0} \\

<u>solve </u><u>the </u><u>parenthesis </u><u>so </u><u>as </u><u>to </u><u>obtain </u><u>simpler </u><u>terms</u>

\bold{\implies \: ( x {}^{2}  + 4x + 4 ) + 4x + 8 - 5 = 0}\\

<u>solve </u><u>the </u><u>like </u><u>terms </u><u>and </u><u>you'll</u><u> </u><u>obtain </u><u>the </u><u>required</u><u> </u><u>equation</u><u> </u><u>!</u>

\bold{\implies \: x {}^{2}  + 8x - 7 = 0}

hope helpful ~

stealth61 [152]2 years ago
4 0

{\large{\red{\mapsto{\maltese{\underline{\green{\boxed{\blue{\underbrace{\overbrace{\pink{\pmb{\bf{Answer:}}}}}}}}}}}}}}

x = -7, -1

Step-by-step explanation:

\sf  {(x + 2)}^{2}  + 4(x + 2) - 5 = 0

let (x + 2) = y

So equation will be

\sf {y}^{2}  + 4y - 5 = 0

Further it becomes quadratic equation

we will solve it by breaking middle term method

\sf  \implies  {y}^{2}  + 5y - y - 5 = 0 \\  \\  \sf  \implies y(y + 5) - 1(y + 5) = 0 \\  \\  \sf \implies (y + 5)(y - 1) = 0

Now put the value of y

\sf \implies (x + 2 + 5)(x + 2 - 1) = 0 \\  \\  \sf  \implies (x + 7)(x + 1) = 0

(x + 7) =0⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀(x + 1) = 0

x = -7⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ x = -1

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Step-by-step explanation:

I'll do 2.

Alright,Alex let say we have factored a quadratic into two binomial, for example

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