Answer:
least to greatest: {61, 61, 61, 178, 179}
Step-by-step explanation:
If the third-largest angle is 61°, the smallest three angles cannot be larger than 183°. Since the total of all angles must be 540°, and the total of the largest two cannot be greater than 179°×2 = 358°, the sum of the smallest three must be at least 540° -358° = 182°.
So, the possible sets of angles with the smallest 3 totaling 182° or 183° are (in degrees) ...
{60, 61, 61, 179, 179} . . . . two modes
(61, 61, 61, 178, 179} . . . . . one mode -- the set you're looking for
Answer:
2(7y+19)
Step-by-step explanation:
14y+38=2(7y+19)
Find slope by calculating rise (change in y) over run (change in x).
1-(-3)/-4-0
4/-4
-1
Final answer: A
Answer:
The number of horses that can eat 4 stacks of hay in 8 days = 56 horses
Step-by-step explanation:
The given parameters are;
The time it takes 16 horses to eat 5 stacks = 35 days
Therefore;
The time it takes 16 horses to eat 5/5 stacks (1 stack) = 35 days/5 = 7 days
The time it takes 16 horses to eat 1 stack of hay = 7 days
The time it takes 16 horses/16 to eat 1 stack of hay = 7 days × 16 = 112 days
Therefore;
The time it takes 1 horse to eat 1 stack of hay = 112 days
The time it takes 1 horse to eat 4 × 1 stack of hay = 112 days × 4 = 448 days
The time it takes 1 horse to eat 4 stacks of hay = 448 days
Therefore, given that (448 days)/(8 days/horse) = 56 horse, we have;
The number of horses that will eat 4 stacks of hay in 8 days = 56 horses.
its -5 so it is A,( -19/2, -5)
