D) square the number and add 2
Answer:

Step-by-step explanation:
Given,
Principal ( P ) = $ 6000
Amount ( A ) = $ 14550
Time ( T ) = 10 years
Rate ( R ) = ?
<u>Finding </u><u>the </u><u>Interest</u>
The sum of principal and interest is called an amount.
From the definition,

plug the values
⇒
Swap the sides of the equation
⇒
Move 6000 to right hand side and change its sign
⇒
Subtract 6000 from 14550
⇒
Interest = $ 8550
<u>Finding </u><u>the </u><u>rate </u>

plug the values
⇒
Calculate
⇒
⇒
Hope I helped!
Best regards!!
I’m not quite sure if I did this right,but 6x+3h
The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.
Step-by-step explanation:
The given is,
Kuroshio Sea tank is 27m long, 35m wide and 10m deep.
Step:1
Sea tank looks like a rectangular prism,
Formula to calculate the volume of rectangular prism,
.............................(1)
Where, w - Width of the rectangular prism
h - Height or depth of the rectangular prism
l - Length of the rectangular prism
From given,
w = 35 meters
l = 27 meters
h = 10 meters
Equation (1) becomes,



Volume of the sea tank, V = 9450 Cubic meters
Result:
The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.
Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i