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drek231 [11]
1 year ago
13

Gavin bakes 70 cookies in an hour , how many cookies can he bake in hour 4

Mathematics
2 answers:
Levart [38]1 year ago
5 0

Answer:

 280 cookies

Step-by-step explanation:

<em>Since, Gavin bakes 70 cookies in an hour that means it is it rate:</em>

<em>70 : 1 or  70/1</em>

<u><em>To Find:</em></u>

<em>How many cookies can he bake in 4 hour</em>

<u><em>Solve:</em></u>

<em>Since in 1 Hour ⇒ 70 cookies</em>

<em>then in 4 Hour ⇒ 70 × 4 = 280</em>

<em />

<em>Now let make a proportion</em>

<em>proportion - an equation in which two ratios are set equal to each other. </em>

<em />\frac{70}{1}=\frac{280}{4}

70 × 4 = 280

1 × 280 = 280

280 = 280

<em>Hence, Gavin can bake 280 cookie in 4 hour.</em>

<em />

<u><em>Kavinsky</em></u>

SIZIF [17.4K]1 year ago
4 0

Answer:

280

Step-by-step explanation:

70x4=280

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What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
Given the functions, and g(x) = 3x 2 + 2, perform the indicated operation. f(g(x))
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I’m not quite sure if I did this right,but 6x+3h
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The Kuroshio Sea tank is 27m long, 35m wide and 10m deep. What is the volume of the tank? Show your
umka21 [38]

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is  27m long, 35m wide and 10m deep.

Step-by-step explanation:

The given is,

                 Kuroshio Sea tank is 27m long, 35m wide and 10m deep.

Step:1

                Sea tank looks like a rectangular prism,

                 Formula to calculate the volume of rectangular prism,

                                   Volume, V =whl.............................(1)

                Where, w - Width of the rectangular prism

                              h - Height or depth of the rectangular prism

                               l - Length of the rectangular prism

              From given,

                       w = 35 meters

                         l = 27 meters

                        h = 10 meters

             Equation (1) becomes,

                                              V = (35)(10)(27)

                                                  = (945)(10)

                                                 =9450

      Volume of the sea tank, V = 9450 Cubic meters

Result:

         The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is  27m long, 35m wide and 10m deep.

           

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Answer:

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Step-by-step explanation:

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If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.

x + 8 = 0

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x = √-36 ... square root of an imaginary number produces the usual square root and an "i"

x = ±6i

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2 years ago
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