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mrs_skeptik [129]
2 years ago
7

Please and thank you

Mathematics
2 answers:
KatRina [158]2 years ago
8 0

Answer:

\huge\boxed{\sf x = 4}

Step-by-step explanation:

If the given polygon is a regular polygon, its sides are equal.

This means:

x^2+4=x^2+x

Subtract x^2 to both sides

4 = x

OR

x = 4

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
serg [7]2 years ago
3 0

<em>The given polygon is a square which means its all sides will be equal.</em>

<h3>According to the above statement:-</h3>

\tt \: x ^{2}  + x = x ^{2}  + 4

Let's solve it ~

\tt \cancel{x ^{2} } + x =  \cancel{x ^{2} } + 4

\tt \: x = 4

\rule{300pt}{3pt}

\huge{|\underline{\mathtt{\red{S}\blue{i}\orange{d}\pink{e}\blue{s}\purple{:}\green{-}\red{}\blue{}\orange{}}}}

\sf \: x ^{2}  + x \\  \sf \:  4 ^{2}  + 4 \\  \sf \: 16 + 4 \\  \sf \: 20

Thus, The sides of the polygon will be 20cm each!

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A person places $81200 in an investment account earning an annual rate of 3.6%, compounded continuously. Using the formula V = P
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Work out the area of this circle.
Vlada [557]

Answer:

530.998cm^2

Step-by-step explanation:

General formula for the area of a circle is πr^2

And π is given to be 3.142

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So let's apply the formula

Area=3.142×(13^2)

Area=3.142×169

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6 0
3 years ago
Skye had 12 1/4 meters of ribbon. She used 2/3 of it to wrap a present and 1/2 of the remainder on a craft project. How many met
LenaWriter [7]

Answer:

She has 2 1/24 meters of ribbon

Step-by-step explanation:

Skye has 12 1/4 meters of ribbon, and she uses 2/3 of that.

To know how much she uses we have to multiply the total by the fraction she uses:

12 1/4 * 2/3,

12 1/4 is the same as 49/4, so we can solve by multiplying the nominators and denominators:

49/4 * 2/3 = 49/6;

So she used 49/4 meters of ribbon or 8.167 m.

Now we are going to see how much ribbon is left by subtracting from the total what she used:

12 1/4 - 49/4 = 49/12 meters that she has left.

And out of those she uses 1/2, so we are going to multiply what she has left by 1/2:

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And because she used half she still has the other half of the remaining:

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8 0
3 years ago
What additional information would he need to prove the triangles are congruent using the Side-Angle-Side method?
garri49 [273]

Answer:

\angle A \cong \angle D

Step-by-step explanation:

Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.

∆ABC and ∆DEF has been drawn as shown in the attachment below.

We are given that \overline{AB} \cong \overline{DE} and also \overline{AC} \cong \overline{DF}.

In order to prove that ∆ABC \cong ∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.

The included angle has been shown in the ∆s drawn in the diagram attached below.

Therefore, the additional information that would be need is:

\angle A \cong \angle D

3 0
3 years ago
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